Get web path

Hello---

This is probably a very newbish question, so please bear with me.

How can I get the "web directory" of the program?

ie. If I have a script running in "localhost/test/inc/test.php", how can I retrieve the value "localhost/test"?

I hope that makes sense. Please let me know if it doesn't, or if you need anymore information.

Thank you in advance for your help!

 

try

echo $_SERVER["SCRIPT_NAME"];

this will output something like this

test/inc/test.php

you will need to use explode function get the correct information form the output

 

If you've opened /includes/system/config.php, it will say that your path is /includes/system/ :

<?php
function getScriptPath() {
     $self = $_SERVER['PHP_SELF'];
     preg_match('/(.*)\/[a-zA-Z0-9.php]/', $self, $path);
     $full_path = $path[1] . "/";
     return $full_path;
}
?>

PHP:

Another easy way to get your current file & path :

<?php
$file_and_path = __FILE__;
echo $file_and_path;
?>

PHP:

 

using __FILE__ it's the easiest method.

 

And once you have __FILE__ , dirname() will strip a file/directory name off the right side.

e.g.,

echo dirname(dirname(__FILE__));

Code (markup):

will get you what you're after in this case.

 

Thank you everyone for your suggestions! However, I didn't quite type what I wanted right ( I was really tired..... )

I am looking for something where if the script is running in "http://localhost/test/inc/test.php", to get the "http://localhost/test" part. (I left out the http:// )

Any ideas on how to get that?

Once again, thank you all for your help!

 

I got it. Thank you to everyone for their help.

I modified ActiveFrost's script a slight bit. Here is my new script for anyone who's interested:
<?php
function getScriptPath() {
$self = explode("/",$_SERVER['PHP_SELF']);
echo $_SERVER['SERVER_NAME'].":".$_SERVER['SERVER_PORT']."/".$self[1];
}

getScriptPath();
?>

Thank you everyone! You have been so helpful!