generate dynamic content in one page

Hi all..

I am new in php and mysql,

I have a question:

I have an home page, there are three links : news1, new2 and news3.

and then I have one page to display the news, display.php.

Can I display news1,news2,news3 in display.php. So I dont need to make

3 different page (display1.php, display2.php, display3.php) to display

3 different content (news1, new2 and news3)

I want to make it dynamic.


many thanks

 

yep, one way is, it is done by declaring a parameter.

u must have a "container" using css where you will put all those links..
and then call for the parameters..

<a href="display.php?parameter=1">news1</a>
<a href="display.php?parameter=2">news2</a>
<a href="display.php?parameter=3">news3</a>
for example:

display.php

<a href="display.php?parameter=1">news1</a> 
<a href="display.php?parameter=2">news1</a>
<a href="display.php?parameter=3">news1</a>

$parameter = $_GET['parameter'];

switch($parameter) // switch statement is under the container
{
   case 1:
       include("news1.php");
   break;

   case 2:
       include("news2.php");
   break;

   case 3:
       include("news3.php");
   break;
}

PHP:

hope this help..

 

i think, that bartolay13's code not safety...

$default = 1;
$url[1]="news1.php";
$url[2]="news2.php";
$url[3]="news3.php";

if(isset($_GET["page"])) 
{
$page=intval($_GET["page"]);
if($page<1 or $page>count($url)) $page=1;
if(@$url[$page]=='') $page=1;
include($url[$page]);
}
include($url[$default]);

Code (markup):

 

OK many thx, i'll try it