i need to validate a field in a form where a user enters a reference number this can be letters, numbers and special characters also so i have not written any special preg match as the username is a combination. the only check i am doing is if there are any white spaces and if a user simple presses the space bar and does not enter value i display a message to enter the reference number and even if there are white spaces followed by the reference number i have used trim method. i have checked in the database even if there are white spaces followed by reference number due to trim() method the data in the table is being inserted whithout those white spaces. following is the code i am presently using $referencenumber = trim($_POST["referencenumber"]); if(strlen($referencenumber) == 0) { $error.="<li>Reference number cannot be blank </li> <br />"; } this code works perfectly fine and does what it is supposed to, however i am using techniques to avoid sql injection. following is the technique i have used if(get_magic_quotes_gpc()) { $username = stripslashes($_POST["username"]); } else { $username = $_POST["username"]; } due to this even if i use if(get_magic_quotes_gpc()) { $lodgementnumber = stripslashes($_POST["lodgementnumber"]); } else { $lodgementnumber = trim($_POST["lodgementnumber"]); } if(strlen($lodgementnumber) == 0) { $error.="reference number cannot be blank; } the validation is not doing what it does in the code i mentioned at the begining. i need to use techniques to avoid sql injection and i also need the validation to work. how can i fix this. please advice. thanks.
hmm, okay, If your SQL injection protection works fine, then I can help you out with form validation. try this : if(get_magic_quotes_gpc()) { $lodgementnumber = stripslashes($_POST["lodgementnumber"]); } else { $lodgementnumber = trim($_POST["lodgementnumber"]); } if($lodgementnumber == "" || empty($lodgementnumber)) { $error = 'reference number cannot be blank'; } try it, and if you have other validators too ( multiple $error) then just add a ' . ' before the equals-to sign after $error Regards, Nasty Nappy
thanks for replying. i have used the code you suggested. if(get_magic_quotes_gpc()) { $lodgementnumber = stripslashes($_POST["lodgementnumber"]); } else { $lodgementnumber = trim($_POST["lodgementnumber"]); } if($lodgementnumber == "" || empty($lodgementnumber)) { $error = 'reference number cannot be blank'; } this code is not able to recognise when i press the space bar and create blank spaces. i have also tried the following if($lodgementnumber == "" || strlen($lodgementnumber) == 0 ) {} even this is not working. please advice how i can fix this. thanks