Fatal error, PHP5 problem

The following piece of code is now causing this error:

         $recipe_item = '<select name="recipe_item">';
         for( $i = 0; $i < count($item_list); $i++ )
         {
            $recipe_item[$i]['item_name'] = adr_get_lang($item_list[$i]['item_name']);
            $recipe_item .= '<option value = "'.$item_list[$i]['item_id'].'" >' . $item_list[$i]['item_name'] . '</option>';
         }
         $recipe_item .= '</select>'; 

PHP:

Now, I've read that PHP5 doesn't always handle this code the same way as PHP4, and that it's the $recipe_item[$i] bit that's causing problems, but I don't know how to fix it. Especially if there's a way to alter it so that it still works with PHP4.

 

What is you are actually trying to do, because $recipe_item isnt an array

 

$recipe_item[$i]['item_name']

Code (markup):

Prior to that you're treating $recipe_item as a string. The error comes up because the above sniplet is trying to reference an index of an index.

If $recipe_item[$i] was an array, then $recipe_item[$i]['item_name'] could exist.
However, since $recipe_item is a string, $recipe_item[$i] is a single character, not an array.

 

The code is used to create a drop-down list. It works fine in PHP4, but some people have had problems with it in PHP5.

 

Try change loop to this:

for( $i = 0; $i < count($item_list); $i++ )
 {
	$recipe_item .= '<option value = "'.$item_list[$i]['item_id'].'" >' . adr_get_lang($item_list[$i]['item_name']) . '</option>';
 }

PHP:

 

Thanks, that seems to have worked.