Extracting href's from page that contain certain text

Hi,

I would like to extract from a string the value of all <A HREF> nodes that contain the text ".MBR". Can anyone suggest how to do this?

Example
--------

String is:

$str = "<A HREF=/location/$file/filename.MBR> <font size="1" face="Arial> <A HREF=/location/$file/filename.htm><A HREF=/location/$file/filename2.MBR>";

Desired result is:

"/location/$file/filename.MBR" and "/location/$file/filename2.MBR"

I think that preg_match_all and preg_replace are probably the way to do this, but I don't know what the syntax for the patterns should be? Is there are good resource for describing the syntax of patterns?

Thanks in advance,

Ade

 

preg_match_all('~\s+href=["\']?(.+\.MBR)["\'>]~si', $text, $matches);

print_r($matches[1]);

PHP:

Untested but should work.

 

Thanks for your response nico_swd.

I tried your suggestion and the result was:

Array
(
[0] => /location/$file/filename.MBR> <font size="1" face="Arial> <A HREF=/location/$file/filename.htm><A HREF=/location/$file/filename2.MBR
)

Any idea how I can get the following result in an array?:

"/location/$file/filename.MBR" and "/location/$file/filename2.MBR"

 

$str = '<A HREF=/location/$file/filename.MBR> <font size="1" face="Arial> <A HREF=/location/$file/filename.htm><A HREF=/location/$file/filename2.MBR>';

//Match all links
preg_match_all('/<a href=(.*)>/Uis',$str,$results);

/*
or only match MBR
preg_match_all('/<a href=(.*\.MBR)>/Uis',$str,$results);
*/

print_r($results[1]);

PHP:

Peace,