Extracting exact browser name from HTTP_USER_AGENT variable

Hi man

I am trying to store browser name of visitor into database. I tried HTTP_USER_AGENT variable but it shows a long long sentence in which browser name is available.

Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.9.2.16) Gecko/20110319 AlexaToolbar/alxf-2.01 Firefox/3.6.16

I access this test php file from different browsers but Mozilla in appearing in all browsers. How to extract exact and short browser name from this variable like Mozilla Firefox, Internet Browser, Google Chrome, Opera, etc?

GCS

 

Here is a function that I found on this page http://php.net/manual/en/function.get-browser.php. I think it does what you are looking for.
(no copyright violation intended here.)

function getBrowser()
{
    $u_agent = $_SERVER['HTTP_USER_AGENT'];
    $bname = 'Unknown';
    $platform = 'Unknown';
    $version= "";

    //First get the platform?
    if (preg_match('/linux/i', $u_agent)) {
        $platform = 'linux';
    }
    elseif (preg_match('/macintosh|mac os x/i', $u_agent)) {
        $platform = 'mac';
    }
    elseif (preg_match('/windows|win32/i', $u_agent)) {
        $platform = 'windows';
    }
   
    // Next get the name of the useragent yes seperately and for good reason
    if(preg_match('/MSIE/i',$u_agent) && !preg_match('/Opera/i',$u_agent))
    {
        $bname = 'Internet Explorer';
        $ub = "MSIE";
    }
    elseif(preg_match('/Firefox/i',$u_agent))
    {
        $bname = 'Mozilla Firefox';
        $ub = "Firefox";
    }
    elseif(preg_match('/Chrome/i',$u_agent))
    {
        $bname = 'Google Chrome';
        $ub = "Chrome";
    }
    elseif(preg_match('/Safari/i',$u_agent))
    {
        $bname = 'Apple Safari';
        $ub = "Safari";
    }
    elseif(preg_match('/Opera/i',$u_agent))
    {
        $bname = 'Opera';
        $ub = "Opera";
    }
    elseif(preg_match('/Netscape/i',$u_agent))
    {
        $bname = 'Netscape';
        $ub = "Netscape";
    }
   
    // finally get the correct version number
    $known = array('Version', $ub, 'other');
    $pattern = '#(?<browser>' . join('|', $known) .
    ')[/ ]+(?<version>[0-9.|a-zA-Z.]*)#';
    if (!preg_match_all($pattern, $u_agent, $matches)) {
        // we have no matching number just continue
    }
   
    // see how many we have
    $i = count($matches['browser']);
    if ($i != 1) {
        //we will have two since we are not using 'other' argument yet
        //see if version is before or after the name
        if (strripos($u_agent,"Version") < strripos($u_agent,$ub)){
            $version= $matches['version'][0];
        }
        else {
            $version= $matches['version'][1];
        }
    }
    else {
        $version= $matches['version'][0];
    }
   
    // check if we have a number
    if ($version==null || $version=="") {$version="?";}
   
    return array(
        'userAgent' => $u_agent,
        'name'      => $bname,
        'version'   => $version,
        'platform'  => $platform,
        'pattern'    => $pattern
    );
}

// now try it
$ua=getBrowser();
$yourbrowser= "Your browser: " . $ua['name'] . " " . $ua['version'] . " on " .$ua['platform'] . " reports: <br >" . $ua['userAgent'];
print_r($yourbrowser);

PHP:

 

Once again thank you john, your code worked and you can check it here http://www.globalcashsite.com/system.php

Your code gave me an additional information that is platform but I don't understand what is report variable and what is purpose of this?

GCS

 

Hi John,

I have a question what if visitor browser is not among all these assumed in your code then there should also be "other" possibility, can you please add this in your code and let me know?

GlobalCashSite