Erorr syntax error, unexpected T_STRING

Discussion in 'PHP' started by PHP Boy, Jul 4, 2011.

0
  1. #1
    Hi :)

    What is problem in my code ??

    My code:
    copy($HTTP_POST_FILES['ufile']['tmp_name'][0], $path1); //line 12
copy($HTTP_POST_FILES['ufile']['tmp_name'][1], $path2);
copy($HTTP_POST_FILES['ufile']['tmp_name'][2], $path3);
    PHP:
    Sorry , My language is weak :(
     
    PHP Boy, Jul 4, 2011 IP
  2. ker

    ker Peon

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    #2
    Can You give us more lines?
    It may be problem in line 11...
     
    ker, Jul 4, 2011 IP
  3. vruvishal

    vruvishal Member

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    #3
    could you put whole file code?
     
    vruvishal, Jul 4, 2011 IP
  4. PHP Boy

    PHP Boy Peon

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    #4
    OK!! OK!!

    multiple_upload.php
    
<table width="500" border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#CCCCCC">
<tr>
<form action="multiple_upload_ac.php" method="post" enctype="multipart/form-data" name="form1" id="form1">
<td>
<table width="100%" border="0" cellpadding="3" cellspacing="1" bgcolor="#FFFFFF">
<tr>
<td><strong>multiple Files Upload </strong></td>
</tr>
<tr>
<td>1.Select file
<input name="ufile[]" type="file" id="ufile[]" size="50" /></td>
</tr>
<tr>
<td>2.Select file
<input name="ufile[]" type="file" id="ufile[]" size="50" /></td>
</tr>
<tr>
<td>3.Select file
<input name="ufile[]" type="file" id="ufile[]" size="50" /></td>
</tr>
<tr>
<td align="center"><input type="submit" name="Submit" value="Upload" /></td>
</tr>
</table>
</td>
</form>
</tr>
</table>
    PHP:
    multiple_upload_ac.php
    
<?php

//تعيين المجلد الذي تريد تخزين الصور عليه
//في هذا المثال سنحفظ الملف في مجلد upload
//$HTTP_POST_FILES['ufile']['name']; = اسم الملف المرفوع
//على سبيل المثال رفعنا ملف باسم test.gif فسوف يكون مسار الصورة upload/test.gif
$path1= "upload/".$HTTP_POST_FILES['ufile']['name'][0];
$path2= "upload/".$HTTP_POST_FILES['ufile']['name'][1];
$path3= "upload/".$HTTP_POST_FILES['ufile']['name'][2]

//نسخ الملف الى حيث تريد تخزين الملف
copy($HTTP_POST_FILES['ufile']['tmp_name'][0], $path1); //line 12
copy($HTTP_POST_FILES['ufile']['tmp_name'][1], $path2);
copy($HTTP_POST_FILES['ufile']['tmp_name'][2], $path3);

//$HTTP_POST_FILES['ufile']['name'] = اسم الملف
//$HTTP_POST_FILES['ufile']['size'] = حجم الملف
//$HTTP_POST_FILES['ufile']['type'] = نوع الملف
echo "File Name :".$HTTP_POST_FILES['ufile']['name'][0]."<BR/>";
echo "File Size :".$HTTP_POST_FILES['ufile']['size'][0]."<BR/>";
echo "File Type :".$HTTP_POST_FILES['ufile']['type'][0]."<BR/>";
echo "<img src=\"$path1\" width=\"150\" height=\"150\">";
echo "<P>";

echo "File Name :".$HTTP_POST_FILES['ufile']['name'][1]."<BR/>";
echo "File Size :".$HTTP_POST_FILES['ufile']['size'][1]."<BR/>";
echo "File Type :".$HTTP_POST_FILES['ufile']['type'][1]."<BR/>";
echo "<img src=\"$path2\" width=\"150\" height=\"150\">";
echo "<P>";

echo "File Name :".$HTTP_POST_FILES['ufile']['name'][2]."<BR/>";
echo "File Size :".$HTTP_POST_FILES['ufile']['size'][2]."<BR/>";
echo "File Type :".$HTTP_POST_FILES['ufile']['type'][2]."<BR/>";
echo "<img src=\"$path3\" width=\"150\" height=\"150\">";

///////////////////////////////////////////////////////

// يستخدم هذا الكود لعرض نجاح الرفع او فشله

$filesize1=$HTTP_POST_FILES['ufile']['size'][0];
$filesize2=$HTTP_POST_FILES['ufile']['size'][1];
$filesize3=$HTTP_POST_FILES['ufile']['size'][2];

if($filesize1 && $filesize2 && $filesize3 != 0)
{
echo "تم رفع الملف بنجاح";
}

else {
echo "فشل رفع الملف";
}

//////////////////////////////////////////////

// الملفات التي لديها مشاكل ان وجدت

if($filesize1==0) {
echo "هناك خطأ في الملف الاول";
echo "<BR />";
}

if($filesize2==0) {
echo "هناك خطأ في الملف الثاني";
echo "<BR />";
}

if($filesize3==0) {
echo "هناك خطأ في الملف الثالث";
echo "<BR />";
}

?>
    PHP:
     
    PHP Boy, Jul 4, 2011 IP
  5. ker

    ker Peon

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    #5
    You didn't put ; at end of line 9.
    Should work now...
     
    ker, Jul 5, 2011 IP
  6. PHP Boy

    PHP Boy Peon

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    #6
    Yes :)
    thank you for help me :)
     
    PHP Boy, Jul 5, 2011 IP