Echo dissappears after adding another one?

Hi I have just started learning php a few weeks ago and was happily modifying my website until i met with this really confusing problem that has been troubling me all day long.I created a Layout Table and drew 3 Layout cell (I'm using Dreamweaver).Then i did three different php scripts and pasted it to the 3 cells.Problem is, when i pasted the 3rd php script in the 3rd Cell,the php script at the 2nd cell wont show up!If i take out the 2nd php script in the 2nd cell the 3rd script will be visible!these two scripts just can't coexist with each other and i can't seem to find what went wrong anywhere...

This code is before i insert the 3rd php script:



<br>
<?php
echo $row[search]
?>

<!--<table class="wd750" align="center">
<tr>
<td class="usp"><span class="tagline">$row[banner]</td>

</tr>
</table>
-->

<table class="wd750" align="center">
<tr>
<td class="hrhdlL"><span class="tagline"><strong>Browse&nbsp;by&nbsp;category</strong></span></td>
</tr>
</table>
<hr>
<table width=100% cellspacing="5" cellpadding="0">
<!--DWLayoutTable-->
<tr>
<td width="138" height="157" valign="top"><p>&nbsp;</p>
</td>
<td width="657" valign="top">
<table width=100%>
<!--DWLayoutTable-->
<tr>
<td height="21" valign="top">
<br> <?php
echo $row[displaycat]
?></td>
</tr>
<tr>
<td width="634" height="128">&nbsp;</td>
</tr>





<!--DWLayoutTable-->
</table></td>
<td width=152 valign="top" nowrap><p class="tagline"></p>
<p class="tagline"> </p>
<?php
$con = mysql_connect("localhost","root","");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}

mysql_select_db("2u2ia", $con);

$result = mysql_query("SELECT * FROM textad limit 10");

while($row = mysql_fetch_array($result))
{
$siteurl = $row["link"];
$sitetext = $row["text"];
echo ("<a href='http://$siteurl'>$sitetext </a>");
echo "<br />";
echo "<br />";

}

mysql_close($con);
?>
<p>&nbsp; </p> <p>&nbsp; </p></td>
</tr>
</table>
=========================================================
and this is after i added the 3rd script:



<br>
<?php
echo $row[search]
?>

<!--<table class="wd750" align="center">
<tr>
<td class="usp"><span class="tagline">$row[banner]</td>

</tr>
</table>
-->

<table class="wd750" align="center">
<tr>
<td class="hrhdlL"><span class="tagline"><strong>Browse&nbsp;by&nbsp;category</strong></span></td>
</tr>
</table>
<hr>
<table width=100% cellspacing="5" cellpadding="0">
<!--DWLayoutTable-->
<tr>
<td width="138" height="157" valign="top"><p>&nbsp;<?php
$con = mysql_connect("localhost","root","");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}

mysql_select_db("2u2ia", $con);

$result = mysql_query("SELECT * FROM bannerad ");

while($row = mysql_fetch_array($result))
{
$siteurl = $row["banlink"];
$filename = $row["banname"];
$adid = $row["bannerid"];

echo ("<a href='http://$siteurl'><img border=\"2\" src=\"banners/$filename\" width=\"100\" height=\"50\"></a>");
}

mysql_close($con);
?></p>
</td>
<td width="657" valign="top">
<table width=100%>
<!--DWLayoutTable-->
<tr>
<td height="21" valign="top">
<br> <?php
echo $row[displaycat]
?></td>
</tr>
<tr>
<td width="634" height="128">&nbsp;</td>
</tr>





<!--DWLayoutTable-->
</table></td>
<td width=152 valign="top" nowrap><p class="tagline"></p>
<p class="tagline"> </p>
<?php
$con = mysql_connect("localhost","root","");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}

mysql_select_db("2u2ia", $con);

$result = mysql_query("SELECT * FROM textad limit 10");

while($row = mysql_fetch_array($result))
{
$siteurl = $row["link"];
$sitetext = $row["text"];
echo ("<a href='http://$siteurl'>$sitetext </a>");
echo "<br />";
echo "<br />";

}

mysql_close($con);
?>
<p>&nbsp; </p> <p>&nbsp; </p></td>
</tr>
</table>
=======================================================
Somebody help me......

 

Just I can say that you missed ; twice;

May be that is the problem.

echo $row[search] ;


echo $row[displaycat] ;

 

What YIAM says should be the case. You need semi colon to end a statement.

Echo will not overlap. It will list everything out. Example:

echo "My";
echo " name";
echo " is";

PHP:

The output will be as follow

My name is

Code (markup):

 

no,friend,i think there is another problem

check $row[banner]
you didn't use <? ?> and you didn't use echo();
so it's uselss.
please be patient,when you begin to step into the php world
hope this helps.

/s

 

I have put the semicolons but the problem is still there. for the $row[banner] i already put <!-- and --> because i don't want to display it at this moment...
Is it possible that the 2nd php script used up the space and the 3rd php script was unable to squeeze in? I have attached the screenshots for
1)before i pasted the 3rd php script
2) and after i pasted the 3rd php script
at wwwsabahholidaycom/why.html

 

I finally managed to get all the php scripts to appear. For this part "<?php
echo $row[displaycat]?>" i had to make a direct connection to the mysql database like the other two scripts.Thanks guys for pointing out my mistakes >v<