dropping my domain name path from url link

A url path is sent back to my page from a search box. When I click on the link which displays correctly, the address in my address bar adds my domain name which then stops the page being loaded and I get the 404 error. The part of the code where I am having trouble is: (Thank you in advance if you are able to help!)

$query = "select * from movie where movie_title like \"%$trimmed%\"
order by movie_title"; // EDIT HERE and specify your table and field names for the SQL query

$numresults=mysql_query($query)or die (mysql_error());
$numrows=mysql_num_rows($numresults) or die (mysql_error());
// If we have no results, offer a google search as an alternative

if ($numrows == 0)
{
echo "<h4>Results</h4>";
echo "<p>Sorry, your search: &quot;" . $trimmed . "&quot; returned zero results</p>";

// google
echo "<p><a href=\"http://www.google.com/search?q="
. $trimmed . "\" target=\"_blank\" title=\"Look up
" . $trimmed . " on Google\">Click here</a> to try the
search on google</p>";
}

// next determine if s has been passed to script, if not use 0
if (empty($s)) {
$s=0;
}

// get results
$query .= " limit $s,$limit";
$result = mysql_query($query) or die("Couldn't execute query");

// display what the person searched for
echo "<p>You searched for: &quot;" . $var . "&quot;</p>";

// begin to show results set
echo "The following results have been found:";
echo "<br />";
$count = 1 + $s ;

// now you can display the results returned
while ($row= mysql_fetch_array($result)) {
$title = $row["movie_link"];
$title_encoded = urlencode($title);
echo "<a href=" . $title_encoded . ">" . $title . "</a>";
echo "<br />";
//echo "$count.)&nbsp;$title" ;
$count++ ;
}

$currPage = (($s/$limit) + 1);

//break before paging
echo "<br />";

// next we need to do the links to other results
if ($s>=1) { // bypass PREV link if s is 0
$prevs=($s-$limit);
print "&nbsp;<a href=\"$PHP_SELF?s=$prevs&q=$var\">&lt;&lt;
Prev 10</a>&nbsp&nbsp;";
}

// calculate number of pages needing links
$pages=intval($numrows/$limit);

// $pages now contains int of pages needed unless there is a remainder from division

if ($numrows%$limit) {
// has remainder so add one page
$pages++;
}

// check to see if last page
if (!((($s+$limit)/$limit)==$pages) && $pages!=1) {

// not last page so give NEXT link
$news=$s+$limit;

echo "&nbsp;<a href=\"$PHP_SELF?s=$news&q=$var\">Next 10 &gt;&gt;</a>";
}

$a = $s + ($limit) ;
if ($a > $numrows) { $a = $numrows ; }
$b = $s + 1 ;
echo "<p>Showing results $b to $a of $numrows</p>";

?>

</body>
</html>

 

I have just solved this problem, but if anyone else was having the same problem you need to use the htmlspecialchars to drop your domain name showing up as well $title_encoded = htmlspecialchars($title);