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Displaying this year to next year

Discussion in 'PHP' started by jpinheiro, Aug 9, 2008.

0
  1. #1
    Hey, cant figure out how to get this code to work?

    

<?php

$nextyear  = mktime(0, 0, 0, date("m"),   date("d"),   date("Y")+1);

?>

Copyright &copy; <?php print date("Y"); ?> - <?php print "$nextyear"; ?>
    PHP:
    But Displays:

    Copyright © 2008 - 1249790400

    Why is it showing that instead of 2009
     
    jpinheiro, Aug 9, 2008 IP
  2. nico_swd

    nico_swd Prominent Member

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    #2
    mktime() returns a UNIX timestamp: www.php.net/mktime and not a date in a human readable format.

    You already have what you need, you're just over complicating it. ;)
    
Copyright &copy; <?php print date("Y"); ?> - <?php echo date('Y') + 1; ?>
    PHP:
     
    nico_swd, Aug 9, 2008 IP
  3. jpinheiro

    jpinheiro Peon

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    #3
    lol i had that b4 except i messed up on 1 piece i didnt know what i put this originaly

    

Copyright &copy; <?php print date("Y"); ?> - <?php print date('Y')+1); ?>
    PHP:
    And it Didnt work XD lol
     
    jpinheiro, Aug 9, 2008 IP
  4. nico_swd

    nico_swd Prominent Member

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    #4
    Check your parenthesis. There are too many...
     
    nico_swd, Aug 9, 2008 IP