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Displaying database information errors

Discussion in 'Databases' started by r3v07v3r, Dec 17, 2011.

  1. #1
    Hi everyone,

    I know I am new and I am also quite new to web-design so if you would bare with me...

    I am trying to run a script on my website (Quite simple) The script must search my database and find all 12 rows of information on the query I enter...
    The query I enter could be located in any of the columns and there may be more than one result...

    My columns are
    The error from what I can understand is located around line 35 ("$numrows=mysql_num_rows($numresults);") and then even if I delete that I get no results...

    Here is my HTML:

    <form name="form" action="search.php" method="get">
      <input type="text" name="q" />
      <input type="submit" name="Submit" value="Search" />
    and here is my PHP:

      // Get the search variable from URL
      $var = @$_GET['q'] ;
      $trimmed = trim($var); //trim whitespace from the stored variable
    // rows to return
    // check for an empty string and display a message.
    if ($trimmed == "")
      echo "<p>Please enter a search...</p>";
    // check for a search parameter
    if (!isset($var))
      echo "<p>We dont seem to have a search parameter!</p>";
    //connect to your database ** EDIT REQUIRED HERE **
    mysql_connect("localhost","user1234","password1234"); //(host, username, password)
    //specify database ** EDIT REQUIRED HERE **
    mysql_select_db("database1234") or die("Unable to select database"); //select which database we're using
    // Build SQL Query  
    $query = "select * from Table1234 where SURNAME like '$trimmed'"; // EDIT HERE and specify your table and field names for the SQL query
    // If we have no results, offer a google search as an alternative
    if ($numrows == 0)
      echo "<h4>Results</h4>";
      echo "<p>Sorry, your search: &quot;" . $trimmed . "&quot; returned zero results</p>";
    // google
     echo "<p><a href=\"http://www.google.com/search?q=" 
      . $trimmed . "\" target=\"_blank\" title=\"Look up 
      " . $trimmed . " on Google\">Click here</a> to try the 
      search on google</p>";
    // next determine if s has been passed to script, if not use 0
      if (empty($s)) {
    // get results
      $result = mysql_query($query) or die("Couldn't execute query");
    // display what the person searched for
    echo "<p>You searched for: &quot;" . $var . "&quot;</p>";
    // begin to show results set
    echo "Results";
    $count = 1 + $s ;
    // now you can display the results returned
      while ($row= mysql_fetch_array($result)) {
      $name = $row[1];
      $staff_no = $row[2];
      $Position = $row[3];
      $pass_no = $row[4];
      $dob = $row[5];
      echo "$count.)&nbsp;$name,&nbsp;$staff_no,&nbsp;$Position,&nbsp;$pass_no,&nbsp;$dob" ;
      $count++ ;
    $currPage = (($s/$limit) + 1);
    //break before paging
      echo "<br />";
      // next we need to do the links to other results
      if ($s>=1) { // bypass PREV link if s is 0
      print "&nbsp;<a href=\"$PHP_SELF?s=$prevs&q=$var\">&lt;&lt; 
      Prev 10</a>&nbsp&nbsp;";
    // calculate number of pages needing links
    // $pages now contains int of pages needed unless there is a remainder from division
      if ($numrows%$limit) {
      // has remainder so add one page
    // check to see if last page
      if (!((($s+$limit)/$limit)==$pages) && $pages!=1) {
      // not last page so give NEXT link
      echo "&nbsp;<a href=\"$PHP_SELF?s=$news&q=$var\">Next 10 &gt;&gt;</a>";
    $a = $s + ($limit) ;
      if ($a > $numrows) { $a = $numrows ; }
      $b = $s + 1 ;
      echo "<p>Showing results $b to $a of $numrows</p>";
    Thank you in advance,
    Last edited: Dec 17, 2011
    r3v07v3r, Dec 17, 2011 IP
  2. angelinawillium

    angelinawillium Peon

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    I am also beginner but google will help you or you may search in other search engines.
    angelinawillium, Dec 20, 2011 IP
  3. r3v07v3r

    r3v07v3r Peon

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    I have tried google for days now and I keep changing the code, but i find this the most stable...
    r3v07v3r, Dec 20, 2011 IP
  4. ammoun

    ammoun Active Member

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    I can fix it, I'll need to see the error in action.
    ammoun, Dec 22, 2011 IP
  5. r3v07v3r

    r3v07v3r Peon

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    The replies took too long sorry - I have had to use another script in-order to finish the project intime...

    Thank you for the reply though...
    r3v07v3r, Dec 22, 2011 IP
  6. r3v07v3r

    r3v07v3r Peon

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    I do not know how to lock the thread...

    r3v07v3r, Dec 22, 2011 IP