Decimal To Binary Conversion in Java

Here's My Coding to Convert the Decimal number into Binary for newbie in Java.

/**
 * @(#)Decimal To Binary.java
 *
 *
 * @author: Abdul Basit Ansari
 * @version 1.00 2009/11/26
 */

import javax.swing.*;

class DecimalToBinary
{
	public static void main (String[] args)
		 {
			DecToBin DtoB = new DecToBin();
			DtoB.GetNumber();
			DtoB.Convert();
		 }	
}

class DecToBin
{
	int Decimal;  
	
	void GetNumber()
	{
		String D;
		D = JOptionPane.showInputDialog(null,"Enter Decimal Number:");
		Decimal = Integer.parseInt(D);
		//JOptionPane.showMessageDialog(null,Decimal);
	}
	void Convert()
	{
		int[] A = new int[100];
		int i=0;
		
		System.out.println("Decimal:" + Decimal);
		while(Decimal!=1)
		{
			A[i] = Decimal % 2;
			Decimal = Decimal / 2;
			i++;
		}
		A[i]=1;

		System.out.println("Binary:");				
		for(int b=i; b>=0; b--)
		{
		 //JOptionPane.showMessageDialog(null,Binary);
		 System.out.print(A[b]);
		}
	
		
		
	}
}

Code (markup):

 

give me your suggestion to improve this code.

thanks.

 

I'd change your class and everything to 'integer to binary' as it doesn't support decimals.

 

There is a built in method to get this done in java.
Have a look at http://www.expertcore.org/viewtopic.php?f=11&t=879

 

i know these methods, but i show the logic that how to do this without using builtin function.
this logic also works on c++, vb, php etc

 

ohhh...I though you are looking for a method.

BTW: You may avoid using modulo operator and use bitwise operators like SHIFT, AND, etc...
Example:
values & 1 = 1, if last lsb is 1, i.e. odd number
values & 1 = 0, if last lsb is 0, i.e. even number

(value >> 1) = (value / 2)
(value << 1) = (value * 2)

You may now give a try to write a super efficient decimal to binary converter using these tips.