Creating instance of class A in Class B

Hi All,

I am new to PHP, I am trying to create an instance of class one in class2, but I am not able to complete it.
Please if any of you people can help, it will be of great help. Below is the code.



class DataAccessLayer
{
private $connect_mysqli;

public function __construct()
{
include 'CustomException.class.php';
$this->DatabaseConnectionObject();
}


private function DatabaseConnectionObject()
{
try
{

include 'Config.class.php';
$this->connect_mysqli = new mysqli($Config_HostName,$Config_UserName,$Config_Password,$Config_Database);

if (mysqli_connect_errno())
{
printf("Connect failed: %s\n", mysqli_connect_error());
}
else
{
printf("Connect successful");
}
}
catch(customException $ex)
{
$ex->ProcessErrorMessage();
}
}

}

--------------------------------------------------------------------------

class BusinessLayer
{

private $objDataAccessLayer;

public function __construct()
{
//include 'CustomException.class.php';
$this->Initalize();
}

private function Initalize()
{
include 'DataAccessLayer.class.php';
$this->$objDataAccessLayer = new DataAccessLayer();
print 'tester';
}

}


--------------------------------------------------------------------------

Next is my html page


include 'BusinessLayer.class.php';
$newtest = new BusinessLayer();
--------------------------------------------------------------------------

It goes inside the line "$this->$objDataAccessLayer = new DataAccessLayer();" but it dosenot print the
statement "print 'tester';". If you guys have some answers to this it is appreciated.

Thanks

 

Try changing:

$this->$objDataAccessLayer = new DataAccessLayer();

To:

$this->objDataAccessLayer = new DataAccessLayer();

 

Hey Grunt, Thanks Man.

Very silly from me.