Create a php code to broken link?

I have a code like this:

$myURL = 'http://www.yahoo.com';
preg_match('/<title>(.+)<\/title>/',file_get_contents($myURL),$matches);
$title = $matches[1];
echo"$title";

PHP:

But if I put the link wrong / broken, I see the error:
Warning: file_get_contents () [function.file-get-contents]: php_network_getaddresses: getaddrinfo failed: No such host is known...
How to make php code to validate the url? thanks in advance.

 

What I mean here is that when I enter the url in the text box, the url will be checked whether actually found. If not found, I want to make the error message "Your link was not found!". But if the url can be explored, I want to get the title of the site. What friends can help me make the code to check the URL?

 

$result = file_get_contents("http://someurl/somepage");
if($result === false) {
    // The function returns the read data or FALSE on failure
    echo "An error occurred while attempting to fetch the page!";
    $error = error_get_last();
    var_dump($error);
}

PHP:

Edit

file_get_contents("http://") is a quick and dirty way to fetch http data. If you are interested in getting more information and/or verbose details such as raw http headers, http status codes, error details like dns lookup failure etc, you should use the fsockopen functions, or better, use CURL library.

 

If so, how do I use CURL library to obtain the title of the website? thanks in advance,friends.

 

when
l you want to know for curl library use see php.net for more information
its the best site for its all functionality and use of curl