Count repetition in loop

Hallo!

I have the following issue. An array with repeated items.

How do I can number off duplicate elements.

$arr = array ("a", "a", "b", "c", "c", "c", "d", "d");

foreach ($arr as $item) {

	echo "$item" . "<br>";

}

PHP:

I want the solution to be such

a = 2;
b = 1;
c = 3;
d = 2;

I know the function

array_count_values()

PHP:

, but it must arise by cycle

foreach

PHP:

Thanks!

 

why do you want to iterate when array_count_values() gives you the answer immediately?

 

<?
$uniques = array();
foreach ($arr AS $key => $value)
{
if (array_key_exists($key,$uniques))
{
$uniques[$key] = $value + 1;
}
else
{
$uniques[$key] = 1;
}
}

?>

 

Thank you for quick replay coders!

Haw work this script?

$arr = array ("a", "a", "b", "c", "c", "c", "d", "d");

$uniques = array();
foreach ($arr as $key => $value)
{
if (array_key_exists($key,$uniques))
{
$uniques[$key] = $value + 1;
}
else
{
$uniques[$key] = 1;
}
}

PHP:

If I test it, the result confusing me ....

 

it looks like keys and values are being confused in the last example. Try this:

<?php

$arr = array ("a", "a", "b", "c", "c", "c", "d", "d");

$uniques = array();
foreach ($arr as $key => $value)
{
	if (array_key_exists($value,$uniques))
	{
		$uniques[$value] += 1;
	} else
	{
		$uniques[$value] = 1;
	}
}

?>

PHP:

In the array $arr, the letters are all values and not keys.

Brew

 

Thanks! This work perfect