Combining FOR loop with IF statement

Discussion in 'PHP' started by Grendor, Apr 19, 2005.

0
  1. #1
    For example if I want to color every even(every number that divided with 2 equals mod 0) number red in a sequence of 20. I think it should be something like this, but the coloring doesn't work:

    <html>
    <body>
    <?
    for ($a=1; $a<=20; $a++)
    if ($a % 2=="0") $color="red";
    {
    echo $a;
    echo "<br>";
    }
    echo "<font color=\"$color\">\n";

    ?>
    </body>
    </html>
     
    Grendor, Apr 19, 2005 IP
  2. TommyD

    TommyD Peon

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    #2
    if ($a % 2=="0") $color="red";

    I think you want if ($a % 2== 0 ) $color="red";

    hth,

    tom
     
    TommyD, Apr 19, 2005 IP
  3. T0PS3O

    T0PS3O Feel Good PLC

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    #3
    T0PS3O, Apr 19, 2005 IP
  4. rvarcher

    rvarcher Peon

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    #4 
    
for ( $i=0; $i<=20; $i++)
{
   $color = ($i%2) ? "red" : "black";

   echo "<font color=\"$color\">$i is $color</font><br />\n";
}
    PHP:
     
    rvarcher, Apr 19, 2005 IP
  5. noppid

    noppid gunnin' for the quota

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    #5
    It's not a divisor, it's a modulus operator. :/
     
    noppid, Apr 19, 2005 IP
  6. mushroom

    mushroom Peon

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    #6
    Your syntax is wrong 
    for ($a=1; $a<=20; $a++)
{if ($a % 2=="0")
{ $color="red";
echo $a;
echo "<br>";
}
else { optional statment;}
}
    PHP:
    you are missing the extra " { } "s that makes it work properly, also a "{" must follow the ")"
     
    mushroom, Apr 19, 2005 IP
  7. noppid

    noppid gunnin' for the quota

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    #7 
    
for ($a=1; $a<=20; $a++)
{
	if ($a % 2=="0")
	{ 
		$color="red";
		echo $a;
		echo "<br>";
	}
	else 
	{ 
		optional statment;
	}
}
    PHP:
    I see no problems with the syntax. The problem is when he compares the 0 to "0", php may not type cast the var properly for the test. === may not help either since they are going to cast differently.

    The solution us use the 0 as the comparator. The code is laid out and the braces balance fine.
     
    noppid, Apr 19, 2005 IP