Coding Help {PHP}

hello,

this the code of a torrent search engine i have :

<?php

if ($i == 1) {

$xxx = 1;

echo '

<div class="heading">Related Torrents</div>

	<div id="resultsmain">';

}

    		$verified = 'background: transparent url('._imgdir.'/accept.png) no-repeat scroll right center; -moz-background-clip: -moz-initial; -moz-background-origin: -moz-initial; -moz-background-inline-policy: -moz-initial;';



echo '

	<div class="row">

		<div class="name" style="';

	

	

if (eregi('verified source', $aud[0])) {

    		echo $verified;

				}

$tlink = linkit($name, $id);				

	

echo 'width: 530px">'.$xxx++.' - <a href="'.$tlink.'">'.$name.'</a>

		</div>

		<div class="a">'.$dateposted.'</div>

		<div class="s" style="width: 60px">'.$filesize.'</div>

		<div class="u">'.$seeds.'</div>

		<div class="d wide">'.$leechers.'</div>

		<div class="clearfix"> </div>

	</div>	

';



if($i == $count) {

echo      "</div><br /><br />";

	}



?>

PHP:

the problem is, when i want to view the related torrents down the bottom of the page this error appeared :

Fatal error: Call to undefined function linkit() in /home/findtorr/public_html/inc/print-related.php on line 18

so, can anyone tell me whats wrong with my code?

 

Yeah, you don't have a function called 'linkit'.
This line:

$tlink = linkit($name, $id);

Is setting $tlink to whatever the linkit function returns. I'd guess it's meant to be making a link with the name from the ID, or something like that...

 

You're missing an include() at the top or a function declaration. As iamben said and the error message said, you're missing the linkit() function!