class problem

I've simplified my problem:
I have a simple mysql table set up.

Bands:
id, name, description

Venues:
id, name, address

Events:
id, band_id, venue_id, date



I'm using php5, and like to stick strictly to OOP...but I've been away from OOP for a while and am having issues about class design.

The website I'm creating has a page to list ALL bands, and a page to view just one band (so you can see further info).

At the moment i have 2 classes
One called Band, which deals with getting the band info from the database, and then a bunch of getter functions.
And another called Bands, which get's ALL bands from the database and stores them in an array of Band objects.

I also have a similiar 2 classes for Gigs. (ignore the venues class for now)

So, this means if I just need to access one band for a page, i can use the Band class....but if i want to list all bands, then I can use the Bands class (which deals with an array of Band objects).

I think this is an ok way of doing it...until it comes to implementing the Gigs class.

For example, say if I have one Band object ($myband) and I want to find out $myband's next gig, then i'm thinking i have 2 options
either create functions:
a) $nextgig = $myband->get_next_gig() ---- (returns a gig object)
or
b) $nextgig = $gigs->get_next_gig($myband_id) ---- (returns a gig object)


then i'd have something like

echo $nextgig->get_venue();
echo $nextgig->get_date();


which of the best 2 options is easiest / makes more OOP sense? and is there a better way of designing this problem from an oOP point of view?
the trouble with a) is that $myband would need access to the Gigs Class...yet a) makes more sense "logically" to me ....but then again, b) seems more encapsulated..... It's not that I can't actually do this, I've done it before using various methods...i just want to know the best "OOP" way.

many Thanks for any insights!

 

Id do I personally would use b.

IMO the gigs class should just know about gigs - give it an id - and have it return the object, done.

If you use a - then the myband object which knows about bands - is then going to have to go out and get gig info as well.

You can do it either way I suppose.