Checking input for a number.

The script below puts the input text into an array, it will then check each individual character for a numeric value. If it finds one it will let you know, other wise it will tell you everything is fine.

I'm not sure if there is a more efficient way of doing this, but if you just use

is_numeric($value)

PHP:

and the value is h3llo it will will output telling you it is fine.

<?php

$str = "H3llo Friend";
$max = strlen($str);
$arr1 = str_split($str);

$number = 0;
	
	foreach ($arr1 as $value){
	if (is_numeric($value))
	{
		echo "Number found!";
		exit();
		
	}
	else
	{
		$number++;
	}

	}
	
	if ($number == $max){
		echo "<p>All fine!</p>";
	}


?>

PHP:

Please let me know if there is an easier more efficient way of doing this thanks.

 

if(preg_match('\d', $str)) {
    echo 'String contains a number';
}else{
    echo 'No number found';
}

PHP:

Something like that?

 

Warning: preg_match() [function.preg-match]: Delimiter must not be alphanumeric or backslash in /home/n33t/www/www/numeric.php on line 5
No number found

Code (markup):

That didn't seem to work.

 

Oops, I've only just woke up lol. Use this
if(preg_match('/\d/', $str)) {

 

Well Good Morning!

Thanks for the help that worked perfectly!

 

Morning! No problem

 

Just looking at your mysql_real_escape_string and sprintf function.
Does this prevent SQL Injection?

function mressf()
{
    $args = func_get_args();
    if (count($args) < 2)
        return false;
    $query = array_shift($args);
    $args = array_map('mysql_real_escape_string', $args);
    array_unshift($args, $query);
    $query = call_user_func_array('sprintf', $args);
    return $query;
}

PHP:

 

Yeah it will do

 

Very nice indeed