Check if row exist or not / prepared statement

Hello
I m having trouble with this script it gives this error message
Warning: mysqli_num_rows() expects parameter 1 to be mysqli_result, object given in C:\xampp\htdocs\4.php on line 43

line 43 is if(mysqli_num_rows($stmt) !== 0){

Here is the script

$tid = 1;
/* create a prepared statement */
if ($stmt = mysqli_prepare($link, "SELECT users.username, topics.topic_body FROM `users` LEFT JOIN topics ON topics.topic_author = users.id WHERE topics.id=? order by edit_time ASC")) {
    /* bind parameters for markers */
    mysqli_stmt_bind_param($stmt, "s", $tid);
    /* execute query */
    mysqli_stmt_execute($stmt);
    /* bind result variables */
    mysqli_stmt_bind_result($stmt, $name, $body);
    /* fetch value */
    mysqli_stmt_fetch($stmt);
    if(mysqli_num_rows($stmt) !== 0){
        while (mysqli_stmt_fetch($stmt)) {
            echo "username : <b>[" . $name . "]</b> replay : <b>[" . $body . "]</b><br> " ;
        }
    } else { echo "Not Found"; }
    /* close statement */
    mysqli_stmt_close($stmt);
}
/* close connection */
mysqli_close($link);

PHP:

thanks

 

You're combining procedural and object oriented approaches, when you only want object oriented.

Change if(mysqli_num_rows($stmt) !== 0){

to if(($stmt->num_rows()) !== 0){