Chaning code from radio button to frop down menu

Hello All programers here. Hopefully someone can help me

I am using the free sms script as posted in another thread. I have added more providers to the database which has cause the display to mess up on the index.
What I am wanting to do is switch it from radio buttons to a dropdown menu.

Here's the code for the buttons

function get_providers(){
	echo"<table width='100%'><tr><td width=200' align='left'>";
	$p = 0;
	$query = mysql_query("SELECT * FROM `providers` ORDER BY `name` DESC");
	while($fetch = mysql_fetch_array($query)){
		$p++;
		// Limit 3 per row
		if($p % 7 == 0){
			$new_line = "</td><td width='200' align='left'>";
		}else{
			$new_line = "";
		}
		echo"<input type='radio' value='$fetch[address]' class='radiok' name='prov'> $fetch[name]<br />$new_line";
	}
	echo"</td></tr></table>";
}

Code (markup):

 

function get_providers(){
	echo"<table width='100%'><tr><td width=200' align='left'>";
echo "<select name=\"prov\">";
	$query = mysql_query("SELECT * FROM `providers` ORDER BY `name` DESC");
	while($fetch = mysql_fetch_array($query)){		
		echo"<option value='$fetch[address]'> $fetch[name]</option>\r\n";
	}
echo "</select>";
	echo"</td></tr></table>";
}

Code (markup):

 

I bet you to it and came to post the code I worked out and saw someone had replied. Thanks for your response. I think your code is the same as mine

function get_providers(){
	echo"<table width='100%'><tr><td width=200' align='left'>";
	echo"<select name='prov' >";
	$p = 0;
	$query = mysql_query("SELECT * FROM `providers` ORDER BY `name` ASC");
	while($fetch = mysql_fetch_array($query)){
		echo"<option value='$fetch[address]'> $fetch[name]</option>";
		}
	echo"</select>";
	echo"</td></tr></table>";
}

Code (markup):