can you detect closing broswer and if submit was clicked?

you cant check if submit is already pressed because if they press submit, they wont be on that page anymore

 

question:

body onUnload="checkbutton(this);"

i need to send the form object, how to do that?



PS. good news --- i think i have a solution

 

you saying there is NOT a way to know if the submit button has been pressed, UNLESS you are on the next page?

isn't the onunload event, the last thing that happens before page leaves -- wouldn't the button value be set at that point?

 

< body .... onunload="javascript:checkbutton(document.form1.elements["hid"].value);" >

that does not work?
i have a hidden fields: hid in the form, how can i send that?

 

in case anyone cares

i solved my problem perfectly... with one new thought...

page 1 - submits (data is saved to DB)
then to page 2

using the onunload="javascript:myfunctinoname();"
i call an ajax script that calls a php script that updates the DB record to complete.

so if visitor leaves (record gets completed)
or if user submits page 2 (record gets completed AND same functionality exist--- which was to delete old record and insert new record with both pages of data)

so, the new thought to solved the problem, i completed the record and didn't care about checking if the submit button was pressed or not.

NOTE: i got rid of 2 records issue and the human problem is not a problem because the delete/insert happens back to back -- so no time delay.

thanks for you help

 

Glad I could help.