Can someone tell me what this error message means?

Warning: mysqli_error() expects exactly 1 parameter, 0 given in C:\htdocs\clphp03\new_post09.php on line 112

Line 112 $result = $db->query($sql) or die(mysqli_error());

$db = dbConnect('query');
    $sql = 'SELECT * FROM mammals WHERE postid = $postid';
    $result = $db->query($sql) or die(mysqli_error());
    while ($row = $result->fetch_assoc()) {
        echo $row['postid'];
        }

PHP:

 

i think it is this part of your code $sql = 'SELECT * FROM mammals WHERE postid = $postid';

it should possibly be $sql = "SELECT * FROM mammals WHERE postid = '$postid'";

 

Thanks for the help.

I did what you suggested, but I get the same error message. Perhaps your suggestion corrected part of the problem.

 

I removed or die(mysqli_error()) and I get a new error message.

Fatal error: Call to a member function fetch_assoc() on a non-object in C:\htdocs\clphp03\new_post09.php on line 113

 

Shouldn't line:
$db = dbConnect('query');
be:
$db = new dbConnect('query');

 

Thanks for the help. When I add new I get a different error message.

Fatal error: Class 'dbConnect' not found in C:\htdocs\clphp03\new_post09.php on line 110

 

show full source

 

well, the answer is in your post itself. Click on mysqli_error in your code.

The function accepts a "resource link" argument.. that is giving you the error...

$result = $db->query($sql) or die( mysqli_error( $result ) );

PHP:

alternately, if your $db is a mysqli object ( or inherits mysqli ), you can use

$result = $db->query($sql) or die( $db->error );

PHP:

hopefully this solves...

 

Thank you all for your help.

bvraghav was right on.

I tried or die( mysqli_error( $result ) ); and got nothing. Then I tried or die( $db->error ); and received an error message telling me there was no such table with that name. I forgot to update the name of the table in that last piece of code.