Can someone help me with preg_match ?

Hello I have the following preg_match:

if (preg_match('~^[^0-9]~', $id)) {
echo "<script>alert('no match found.')</script>";

PHP:

It is searching an ID which is made up of numbers like 84773

The problem is, the preg_match still allows 84773+347.3253 for example.

How do I make it only accept numbers like 23 and 39583?

 

With no regular expression at all: http://us1.php.net/ctype_digit

Or.

'~^\d+$~'

PHP:

 

Thank you for the reply.

'~^\d+$~'

PHP:

This seems to still allow periods and + signs.

I tried:

if (!ctype_digit($id)) {
echo "<script>alert('no match found.')</script>";

Code (markup):

Which gave an alert for an all number ID

 

Any one else have any ideas?

I'm trying to give an alert if the ID is anything but a number like 83485 or 344 or 2. No periods, hyphens, plus signs or spaces, etc.

Thanks!

 

I tried with ctype_digit and it worked just fine, you could try is_numeric:

if (!is_numeric($id)) {
echo "<script>alert('no match found.')</script>";
}

PHP:

 

Turns out I was calling the wrong ID... they probably all work, but this one works just fine:

 

is_numeric() accepts values like 0xffff. Not sure if this is a behaviour you're looking for.

 

Good point,
@readezarchive ctype_digit() is probably the best way to go, you should reassign the best answer to nico_swd for post#2.

 

I tested

(!is_numeric($id)

Code (markup):

out with 34243x3434, 33423xffff and it worked correctly. Are you sure?

The Url with the ID it's checking is like google.com/test.php?id=23435

It's checking the ID to make sure it's all numbers with no space, letters or extra characters.