Can not get the link from xvideos

See I consider this code

<?php
error_reporting(E_ERROR | E_PARSE);
function curl_Xvideos($url)
{
    $ch = @curl_init();
    curl_setopt($ch, CURLOPT_URL, $url);
    curl_setopt($ch, CURLOPT_COOKIEFILE, 'cookie.txt');
    $head[] = "Connection: keep-alive";
    $head[] = "Keep-Alive: 300";
    $head[] = "Accept-Charset: ISO-8859-1,utf-8;q=0.7,*;q=0.7";
    $head[] = "Accept-Language: en-us,en;q=0.5";
    curl_setopt($ch, CURLOPT_USERAGENT, 'Mozilla/5.0 (iPhone; U; CPU like Mac OS X; en) AppleWebKit/420.1 (KHTML, like Gecko) Version/3.0 Mobile/3B48b Safari/419.3');
    curl_setopt($ch, CURLOPT_HTTPHEADER, $head);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
    curl_setopt($ch, CURLOPT_ENCODING , 'gzip, deflate');
    curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, FALSE);
    curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, FALSE);
    curl_setopt($ch, CURLOPT_TIMEOUT, 60);
    curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, 60);
    curl_setopt($ch, CURLOPT_FOLLOWLOCATION, TRUE);
    curl_setopt($ch, CURLOPT_HTTPHEADER, array('Expect:'));
    $page = curl_exec($ch);
    curl_close($ch);
    return $page;

     $url = str_replace(' ', '', $url);
        if(!empty($url)):
                curl_setopt($curl = curl_init($url), CURLOPT_RETURNTRANSFER, 1);
                preg_match("/flv_url=(.+)url_bigthumb=([^&]+)/i", curl_exec($curl), $infos);
                curl_close($curl);
                header("Location: ".urldecode($infos[1]));
        endif;
}

function Xvideos($link) {
    $view_source = curl_Xvideos($link);
    $data = explode("new HTML5Player('html5video',", $view_source);
    $data = explode("http://img", $data[1]);
    $data = explode("', '", $data[0]);
    foreach($data as $i => $mp4)
    {
        if(strpos($mp4, '/videos/mp4/'))
        $list .= 'ลิงก์เสริม 360P=>'.trim($mp4).'|';
    }
    return rtrim($list, '|');
}

Code (markup):

 

check pm