can any help with this code pics not showing

am using this code to show details ina table with a pic at the end but not working
cheers
Doug

echo "<table border='1'
cellpadding='5'>
<tr>
<th>Name</th>
<th>Contact</th>
<th>Email</th>
<th>Details</th>
<th>Photo</th>
</tr>";

//Puts it into an array 
while($row = mysql_fetch_array( $result )) 
{ 
//Outputs the image and other data
echo "<tr>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['contact'] . "</td>";
echo "<td>" . $row['email'] . "</td>";
echo "<td>" . $row['details'] . "</td>";
echo "<img src=http://lostpetsplymouth_zxq_net/pics/" . $row['pname'] . "</td>";
echo "</tr>";
}
echo "</table>";

PHP:

 

Try this:

echo "<table border='1'
cellpadding='5'>
<tr>
<th>Name</th>
<th>Contact</th>
<th>Email</th>
<th>Details</th>
<th>Photo</th>
</tr>";

//Puts it into an array 
while($row = mysql_fetch_array( $result )) 
{ 
//Outputs the image and other data
echo "<tr>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['contact'] . "</td>";
echo "<td>" . $row['email'] . "</td>";
echo "<td>" . $row['details'] . "</td>";
echo '<img src=\"http://lostpetsplymouth_zxq_net/pics/".$row['pname']."\" /></td>';
echo "</tr>";
}
echo "</table>";

Code (markup):

That should do it for you, if it doesn't let me know and I can take a deeper look at it, this is just off the top of my head

 

EDIT: Too late...

Back to the basics.... The HTML <img> tag is wrong.

 

oops you did not close the angle bracket of img tag

echo "<img src=\"http://lostpetsplymouth_zxq_net/pics/'.$row['pname'].'\"></td>';


this shd work

Regards

Alex

 

I guess 2 times the same answer wasn't enough yet, huh?

 

lol
nico is right
the whole image tag is wrong.
_net (as opposed to) .net ?

no single or double quotes on the tag (you saw you couldnt use double quotes as it would interfere with the PHP but you cant leave it blank.
and the next thing you wouldve noticed is that you cant use single quotes either BECAUSE you use them on
$row['pname']

what you'll have to do is make it double quotes. AND convert your $row variable to a variable name.. like this

$bigfoot = $row['pname'] ; // called bigfoot for sheets and giggles.

and then your image src tag like this.
echo "<image src='http://lostpetsplymouth_zxq.net/pics/" . $bigfoot . "'></td>";

(assuming that your picture files will have their extensions of .jpg/ .gif/ etc already in tact from where youre fetching them from, if not you'll need to add the extension correctly to if its a .jpg or .gif ...which would be very anal ...so just include the extensions when stored )

strategize the use of single or double quotes.
when you're in a predictament of having both single and double quotes in either variables or string URLs.
then convert variables like $row['single_quote_excessive_use'] to $bigfoot lol

of course it doesnt have to be $bigfoot, although i think it could catch on ..its just nobody would see it if its in your top level php code.
would that make it similar to the real bigfoot? ..i dont know

 

thanks to all for help
but i just cant get it to work
any suggestions as to a better way of doing it
cheers
Doug

 

There's also missing an opening <td> tag in front of the <img> tag.

If that doesn't work either, then there's nothing else we can do as the code is technically correct besides this. Perhaps your URLs are wrong, or the permissions of the files. Can you open the images by entering the URL in the address bar of your web browser?