calling array

Hello,
I build array:

$sites_menu_dropdown = array(
"green.php" => 'green',
"red.php" => 'red',
"blue.php" => 'blue',
"orange.php" => 'orange',
"yellow.php" => 'yellow',
);

now I need to build loop that will print the page name (i.e: green.php) and name (i.e: green) for the first 3 cells (must be in loop).
How can I do that?

Thank you in advance

 

Try this:

$sites_menu_dropdown = array(
"green.php" => 'green',
"red.php" => 'red',
"blue.php" => 'blue',
"orange.php" => 'orange',
"yellow.php" => 'yellow',
);

$n = 0;

foreach($sites_menu_dropdown as $key => $value){
    if($n>=3){ return; }
    echo("<p>".$key." - ".$value."</p>");
    $n++;
}

PHP:

 

Thanks
Why did you use "return"?

 

And why not? Use what you want to break the loop.

 

You only want the first 3 elements. A foreach loop will run until its out of elements. So to break that loop he included that statement so that only 3 elements will be processed.

 

putting "return;" in "foreach" loop will breake the loop?

 

The use of return is not advised in this situation as it will stop executing any code after that loop and return a void to the parent application if any. Instead, use break:

$sites_menu_dropdown = array(
"green.php" => 'green',
"red.php" => 'red',
"blue.php" => 'blue',
"orange.php" => 'orange',
"yellow.php" => 'yellow',
);

$n = 0;

foreach($sites_menu_dropdown as $key => $value){
    if($n>=3){ break;}
    echo("<p>".$key." - ".$value."</p>");
    $n++;
}

PHP: