calendar

Hello,
I have table for assignments
one of the field is "progTargetDate" -> linux time (eg: 1348185600 )
I also built calender and I want to check if I have any assignment for each day I print

so - I wrote the query that bring me all the assignment for the current month

	$query = mysql_query("SELECT ass.id, ass.title, ass.des, ass.progTargetDate 
							FROM pro_assignments AS ass, pro_progs2assignments AS pr 
							WHERE 	(ass.progTargetDate >= $ChoosenMonth_start) AND
									(ass.progTargetDate <= $ChoosenMonth_end) 
							ORDER BY ass.progTargetDate ASC
							");

PHP:

(I delete part of the SQL query))

and I have the loop that build the calendar cell

for ($i = 1 ; $i <= $total_days_in_month ; $i++)
{
}

PHP:

$i = each day in the month

I tried to build IF condition without success
I want to check for each day if it found inside the array (that I got from the first query)

(this code goes inside the FOR loop

echo "<td>$i"; 
		while($index = mysql_fetch_array($query)) 
		{
				$progTargetDate = $index['progTargetDate'];
				if ((mktime(0, 0, 0, date($ChoosenMonth)  , $i, date($ChoosenYear)) == $progTargetDate))
					echo "<p>found</p>";
				else
					echo "<p>not</p>";

		}
									
echo "</td>";

PHP:

What do I do wrong?