Calculate your age by how often you eat out.

timsdd Peon

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#21

Bender said: ↑

And here is the solution (no miracles ):

Probably the best way to see why this works is to avoid committing to
a specific number and see what happens. Instead of picking a number,
I'm going to use 'n' to represent some choice I haven't yet made.

Let's see what happens as I follow the steps:

1) n

2) 2n

3) 2n + 5

4) 100n + 250

5) 100n + (2005 or 2006)

6) 100n + (2004 or 2006) - (year of birth)

Now, let's look at what I ended up with. If we write it this way,

100n + (2005 or 2006) - (year of birth)

= 100n + [(year of my last birthday) - (year of my birth)]

= 100n + [my age]

This might be a good time to note that if you start with a number
greater than 9, or if you're more than 99 years old, the trick won't
work.

So basically, the trick is saying that

50(2n + 5) + 1750 + i - (year of birth)

where i (for 'increment') is the number of years past 2000 for the
year when you had your last birthday, equal to

100n + (your age)

which is, of course, true (for 0 < n < 10, and age < 100):

50(2n + 5) + 1750 + i - (yob)

= (100n + 250) + 1750 + i - (yob)

= 100n + (250 + 1750 + i) - yob

= 100n + (2000 + i) - (yob)

= 100n + (your age)

It is true that with these specific numbers, the trick will work
only this year. However, if you want it to work next year, you can
just change i to '6 or 7' instead of '5 or 6'.

So, in general, you have: a(bn + c) + d + i - (year of birth)

Also see Wikipedia article: http://en.wikipedia.org/wiki/Wikipedia:Reference_desk_archive/Mathematics/June_2006
Click to expand...

___k me! you are a robot!!!

timsdd, Nov 12, 2006 IP

tbarr60 Notable Member

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#22

slipxaway said: ↑

Math is just a hindrance on thought. It's fairly well known that many genuises just arrive at amazing things without really knowing how they got there, then they have to waste time by "doing paperwork" so that the "bureaucrats" can understand it. haha
Click to expand...

Geniuses don't guess there great ideas, they think them through and do it easily. They may take observable first order and second order derivatives and discover things by calculating third order derivatives but they don't do it by just arriving at things.

In this case, it was basically multiply your meal desire by 100 and subtract your birth year from 2006.

tbarr60, Nov 12, 2006 IP

charless Banned

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#23

Cool. Worked!

518!

charless, Nov 12, 2006 IP

myoptimind Peon

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#24

woooh.. wicked... amazing... coooolllll!!!

myoptimind, Nov 12, 2006 IP

Seiya Peon

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#25

Bender said: ↑

And here is the solution (no miracles ):

Probably the best way to see why this works is to avoid committing to
a specific number and see what happens. Instead of picking a number,
I'm going to use 'n' to represent some choice I haven't yet made.

Let's see what happens as I follow the steps:

1) n

2) 2n

3) 2n + 5

4) 100n + 250

5) 100n + (2005 or 2006)

6) 100n + (2004 or 2006) - (year of birth)

Now, let's look at what I ended up with. If we write it this way,

100n + (2005 or 2006) - (year of birth)

= 100n + [(year of my last birthday) - (year of my birth)]

= 100n + [my age]

This might be a good time to note that if you start with a number
greater than 9, or if you're more than 99 years old, the trick won't
work.

So basically, the trick is saying that

50(2n + 5) + 1750 + i - (year of birth)

where i (for 'increment') is the number of years past 2000 for the
year when you had your last birthday, equal to

100n + (your age)

which is, of course, true (for 0 < n < 10, and age < 100):

50(2n + 5) + 1750 + i - (yob)

= (100n + 250) + 1750 + i - (yob)

= 100n + (250 + 1750 + i) - yob

= 100n + (2000 + i) - (yob)

= 100n + (your age)

It is true that with these specific numbers, the trick will work
only this year. However, if you want it to work next year, you can
just change i to '6 or 7' instead of '5 or 6'.

So, in general, you have: a(bn + c) + d + i - (year of birth)

Also see Wikipedia article: http://en.wikipedia.org/wiki/Wikipedia:Reference_desk_archive/Mathematics/June_2006
Click to expand...

Good job, i knew this was the case as soon as it asked for birthdate... lol.

Seiya, Nov 12, 2006 IP

Kassi Peon

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#26

Thatâ€™s a nice approach, what if the age was counted by other physiological factors also related to eating

Kassi, Nov 13, 2006 IP

lpstong Notable Member

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#27

Well I was amused for the most part - till it showed my actual age. Can I say ouch.............................

lpstong, Nov 13, 2006 IP

kocisz Peon

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#28

It worked.. WOOHOOO proud to be a GEEK.. LOL

kocisz, Nov 13, 2006 IP

seouser Peon

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#29

I hate it when fast food dictates my life...

seouser, Nov 14, 2006 IP

slipxaway Active Member

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#30

There is an actual test online you can take, which is health question based, that will calculate your real age based on lifestyle factors. I don't know the address, but I'm sure you could find it. My body is basically 10 years older than I am.. Damn smoking and fast food!

slipxaway, Nov 14, 2006 IP

FlorinI Guest

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#31

It's worked...

FlorinI, Nov 15, 2006 IP

dellux Peon

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#32

stop eating and will stop getting older? lol

dellux, Nov 15, 2006 IP