Calculate your age by how often you eat out.

My mother-in-law sent me this and it kinda freaked me out. If this has already been posted I appolgize, but a search didn't turn anything up.

It worked for both me and my wife. Does it work for everyone else?

 

hehehe

Pretty cool

 

Woah....

This actually works OMFG...lol

That's amazing.

 

yes, it works... that's cool. hehe

 

It works, yes.

 

omggg that is amazing, I wonder how that guy actually though that up, loool

 

perfect, it worked :O
lol..

 

OMFG it works.

 

woah, freaky!

 

some people have too much time on their hands to come up with stuff like this. but it worked

 

I'm glad it's not just me.

I can't help but think that if this person actually channeled their creative energy into something productive we'd have a cure for diabetes already.

 

I got -161, and im 14 not 61.

 

Use a calculator next time

 

nice one, it worked

 

Very good, worked for me .

 

And here is the solution (no miracles ):

Probably the best way to see why this works is to avoid committing to
a specific number and see what happens. Instead of picking a number,
I'm going to use 'n' to represent some choice I haven't yet made.

Let's see what happens as I follow the steps:

1) n

2) 2n

3) 2n + 5

4) 100n + 250

5) 100n + (2005 or 2006)

6) 100n + (2004 or 2006) - (year of birth)

Now, let's look at what I ended up with. If we write it this way,

100n + (2005 or 2006) - (year of birth)

= 100n + [(year of my last birthday) - (year of my birth)]

= 100n + [my age]

This might be a good time to note that if you start with a number
greater than 9, or if you're more than 99 years old, the trick won't
work.

So basically, the trick is saying that

50(2n + 5) + 1750 + i - (year of birth)

where i (for 'increment') is the number of years past 2000 for the
year when you had your last birthday, equal to

100n + (your age)

which is, of course, true (for 0 < n < 10, and age < 100):

50(2n + 5) + 1750 + i - (yob)

= (100n + 250) + 1750 + i - (yob)

= 100n + (250 + 1750 + i) - yob

= 100n + (2000 + i) - (yob)

= 100n + (your age)

It is true that with these specific numbers, the trick will work
only this year. However, if you want it to work next year, you can
just change i to '6 or 7' instead of '5 or 6'.


So, in general, you have: a(bn + c) + d + i - (year of birth)

Also see Wikipedia article: http://en.wikipedia.org/wiki/Wikipedia:Reference_desk_archive/Mathematics/June_2006

 

No, it's magic I tell you!

I considered working it out myself but then realized I'd be better off finding a cure for something. So, here I am with no cure and somebody else beating me to it. Oh well.

 

I stopped as soon as it asked for my birth year. I thought it was going to be magic.

 

This reminds me of the show NUMB3RS, except that's actually cool.

I hate math.

Math is just a hindrance on thought. It's fairly well known that many genuises just arrive at amazing things without really knowing how they got there, then they have to waste time by "doing paperwork" so that the "bureaucrats" can understand it. haha