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Array problem

Discussion in 'PHP' started by selen, Jun 8, 2010.

0
  1. #1
    Hello, I try now to learn arrays, my code:

    	$sourcesnot = mysql_query("SELECT megavideo, novamov, videoweed, movshare, stagevu FROM pm_player_sources WHERE uniq_id = '".$uniqid."'");
	
	while($row5 = mysql_fetch_assoc($sourcesnot))
	{
		$id = $row5;
		
		foreach ($id as $k => $v ) {
			if ($v > 0){
				
				
				
				
				$arr = array($v);
                
				var_dump($arr);
				
			}
    
         }
		
	}
    PHP:
    var_dump($arr) gives me this result:

    Now I have two arrays, but I need only one with 4 and 6
     
    selen, Jun 8, 2010 IP
  2. danx10

    danx10 Peon

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    #2
    danx10, Jun 8, 2010 IP
  3. selen

    selen Well-Known Member

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    #3
    Don't get it and there can be as well more than two, that's just an example these two
     
    selen, Jun 8, 2010 IP
  4. mehmetm

    mehmetm Well-Known Member

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    #4
    is that what u want ?

    
<?php

$sourcesnot = mysql_query("SELECT megavideo, novamov, videoweed, movshare, stagevu FROM pm_player_sources WHERE uniq_id = '".$uniqid."'");

	$arr = array();
    
    while($row5 = mysql_fetch_assoc($sourcesnot)) {
	
        foreach($row5 as $k => $v):
		
			$arr[][$k] = $v;
		
		endforeach;

    }
	
	var_dump($arr);

?>
    PHP:
     
    mehmetm, Jun 8, 2010 IP