array problem

look at these codes plz

$a = array('aw' => 'buw', 'bw' => 'dsf');

$b = "['aw']";

echo $a.$b;

Code (markup):

i wanted the result buw for that but its showing Array['aw']

i know if i use $a['aw'] it will work, but for some reason i need to do it such way


tnx in advance

 

You can use echo $a[$b]; this will work. The way your doing is used for string concatenation not for array mapping.

 

echo $a['aw'];

PHP:

 

why ppl do not read fully b4 reply !!!

btw, @b.krishna: not working man! actually my variable will be like this: $var['som']['data']['link']

the array $var will be created in the php file. but ['som']['data']['link'] is stored in mysql db.

so i wanted to get it maybe in variable $b....so it will be $b = ['som']['data']['link']
thats why i tried like that ($var.$b) to show the array's value

 

You need to step back and explain what you are trying to do rather than trying to come up with a solution yourself and forcing us to get that to work for you. It is more than likely that as a collective we will be able to come up with a better solution to your overall problem.

 

$a = array('aw' => 'buw', 'bw' => 'dsf');
$b = "['aw']";

eval('echo $a'.$b.';');

//OR this if you want to save the result
eval('$c = $a'.$b.';');
echo $c;

PHP:

 

@ShadyStudent: i told that on my 2nd post...i gave full array

@emed: yo...it works. tnx man. thank you very much

 

could just use $a{$b}

EDIT: NVM, you have it

 

$a = array('aw' => 'buw', 'bw' => 'dsf');

$b = "['aw']";

$c=$a.$b;
echo $c;