Another::mysql_result()[function.mysql-result]:Unable to jump to row 0 on..

Discussion in 'PHP' started by jigen7, Nov 9, 2007.

  1. #1
    im getting the errors unable to jump to row........
    not working:
    $sql2 ="Select LinkCategoryID from LinkCategories where LinkCategoryName ='$arr[5]'";
    $result3=mysql_query($sql2,$conn_id);
    $y = 0;
    $count3 = mysql_num_fields($result3);
    while ($y < $count3) {
    $res_linkuserid=mysql_result($result3,$y,"LinkCategoryID"); ;
    $y++;
    }

    is there sumthing wrong with my code i need to get the LinkCategoryID depending on the given LinkCategoryName which is in $arr[5] from table LinkCategories??anyone can help me throughout here because this code is perfectly running but the one i have posted in the upper part is not weird
    working:
    $sql ="Select UserID from Users where UserName = '$user[1]'";
    $result2=mysql_query($sql,$conn_id);
    $x = 0;
    $count2 = mysql_num_fields($result2);
    while ($x < $count2) {
    $res_userid=mysql_result($result2,$x,"UserID");
    $x++;
    }

    ?? thx
     
    jigen7, Nov 9, 2007 IP
  2. armatik

    armatik Peon

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    #2
    Print out $array and see what's going on in there.
     
    armatik, Nov 9, 2007 IP
  3. jigen7

    jigen7 Peon

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    #3
    already printout it says 'Computers' and thats what i want it is but the computer value is in the databse?
     
    jigen7, Nov 9, 2007 IP
  4. armatik

    armatik Peon

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    #4
    What's the error exactly?
     
    armatik, Nov 9, 2007 IP
  5. jigen7

    jigen7 Peon

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    #5
    it gives two errors i only need 1 value
    Warning: mysql_result() [function.mysql-result]: Unable to jump to row 0 on MySQL result index 19 in E:\wwwroot\htdocs\jigen\consolidate\index.php on line 467

    Warning: mysql_result() [function.mysql-result]: Unable to jump to row 0 on MySQL result index 22 in E:\wwwroot\htdocs\jigen\consolidate\index.php on line 467
     
    jigen7, Nov 9, 2007 IP
  6. ajay1375

    ajay1375 Peon

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    #6
    Please help me to solved below mention code.. Error is "Unable to jump to row 0 on MySQL"
    <?php
    $t=0;
    if (isset($_POST["week_date1"]) || isset($_POST["week_date2"]))
    {
    $date1=date('d-m-Y', strtotime($_POST["week_date1"]));
    $date2=date('d-m-Y', strtotime($_POST["week_date2"]));
    $sql2 = "select usid,spid from register";
    $result2 = mysql_query($sql2,$conn);
    $total=mysql_fetch_assoc($result2);
    while ($total<=mysql_fetch_assoc($result2))
    {
    $id=mysql_result($result2,$t,"usid");
    $sql = "select level, count(*) from legcount where spid='$id' and jdate >= '$date1' and jdate <= '$date2' group by level having count(level)>0";
    $result = mysql_query($sql,$conn) ;
    $num=mysql_fetch_assoc($result);
    $i=0;$total=0;$ftotal=0;$ref=0;
    while ($i <= mysql_fetch_assoc($result))
    {
    $f2=mysql_result($result,$i,"count(*)");
    $total=$f2*25;
    $ftotal=$ftotal+$total;
    $i++;

    }

    ?>

    <tr class="tr1" align="center">
    <td><?php echo $id;?></td>
    <td><?php echo $ftotal;?></td>

    <td>0</td>
    <td>0</td>
    <td>0</td>
    </tr>

    <?php
    $t++;
    }
    }
    ?>
     
    ajay1375, Apr 13, 2010 IP