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Ajax Domain Check

Discussion in 'PHP' started by adamjblakey, Dec 20, 2007.

  1. #1
    Hi,

    I was wondering how i would get this script to work in an ajax style. At the moment i have this submitting to another page which checks but would be really good if i could type in the domain and select an ext and it automatically comes up if it available or not.

    Here is the code:

    <?php
    //Domain Checker
    function check_domain($domain,$ext){
    	$server="whois.networksolutions.com";
    	$nomatch="No match for";
    
    	$output="";
    	if(($sc = fsockopen($server,43))==false){
    		return true;
    	}
       	fputs($sc,"$domain.$ext\n");
       	while(!feof($sc)){
    		$output.=fgets($sc,128);
    	}
    	fclose($sc);
    	if (eregi($nomatch,$output)){
    		return true;
    	} else {
    		return false;
        }
    }
    
    //Sample usage
    $is_registered = check_domain("sonimager","com");
    if($is_registered == true){ echo "Domain Taken";}else{echo "Domain is free";}
    
    ?>
    Code (markup):
    Cheers,
    Adam
    SEMrush
     
    adamjblakey, Dec 20, 2007 IP
    SEMrush
  2. Barti1987

    Barti1987 Well-Known Member

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    #2
    Barti1987, Dec 20, 2007 IP
  3. coderbari

    coderbari Well-Known Member

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    #3
    domain.php
    
    <?php
    $domain = $_GET['domain'];
    $ext = $_GET['ext'];
    
    //Domain Checker
    function check_domain($domain,$ext){
    	$server="whois.networksolutions.com";
    	$nomatch="No match for";
    
    	$output="";
    	if(($sc = fsockopen($server,43))==false){
    		return true;
    	}
       	fputs($sc,"$domain.$ext\n");
       	while(!feof($sc)){
    		$output.=fgets($sc,128);
    	}
    	fclose($sc);
    	if (eregi($nomatch,$output)){
    		return true;
    	} else {
    		return false;
        }
    }
    
    //Sample usage
    $is_registered = check_domain($domain , $ext);
    if($is_registered == true){ echo "Domain Taken";}else{echo "Domain is free";}
    
    ?>
    
    PHP:
    ajax.php
    
    <html>
    <head>
    <title>Domain Age Calculator</title>
    <script language="javascript" type="text/javascript"> 
    //Browser Support Code
    function ajaxFunction(){
    	var ajaxRequest;  // The variable that makes Ajax possible!
    	
    	try{
    		// Opera 8.0+, Firefox, Safari
    		ajaxRequest = new XMLHttpRequest();
    	} catch (e){
    		// Internet Explorer Browsers
    		try{
    			ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP");
    		} catch (e) {
    			try{
    				ajaxRequest = new ActiveXObject("Microsoft.XMLHTTP");
    			} catch (e){
    				// Something went wrong
    				alert("Your browser broke!");
    				return false;
    			}
    		}
    	}
    	// Create a function that will receive data sent from the server
    	ajaxRequest.onreadystatechange = function(){
    		if(ajaxRequest.readyState == 4){
    			var ajaxDisplay = document.getElementById('ajaxDiv');
    			ajaxDisplay.innerHTML = ajaxRequest.responseText;
    		}
    	}
    	var domain = document.getElementById('domain').value;
    	var ext = document.getElementById('ext').value;
    	
    	var queryString = "?domain=" + domain + "&ext=" + ext;
    	ajaxRequest.open("GET", "domain.php" + queryString, true);
    	ajaxRequest.send(null); 
    }
    
    </script>		
    </head>
    <body>
    <input type="text" size="30" name="domain" id="domain">
    <select name="ext" id="ext">
    	<option value="">select extension</option>
    	<option value="com">com</option>
    	<option value="org">org</option>
    	<option value="net">net</option>
    	<option value="info">info</option>
    	<option value="edu">edu</option>	
    </select>
    <input type="button" value="Check" onclick="ajaxFunction()"><br><br>
    <b>Enter the domain name without www. Correct</b> = gmail.com <b>Wrong</b> = www.gmail.com
    <br><br>
    <div id="ajaxDiv">The Message will be shown here</div>
    </body>
    </html>
    
    PHP:
    domain.php is the server side script.
     
    coderbari, Dec 20, 2007 IP
  4. adamjblakey

    adamjblakey Active Member

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    #4
    Thanks a lot coderbari's this works great. :)

    Just one thing though, the script comes back with domain name taken even if the domain is available. Any ideas on why this is happening?
     
    adamjblakey, Dec 21, 2007 IP
  5. coderbari

    coderbari Well-Known Member

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    #5
    I also got that error.This is may be bcoz of your written codes.I have no idea about that part.You wanted it to AJAXify and i gave you the idea.
     
    coderbari, Dec 21, 2007 IP
  6. Barti1987

    Barti1987 Well-Known Member

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    #6
    Debug

    After
    fclose($sc);

    Add
    echo $output;

    Read what it has.

    Peace,
     
    Barti1987, Dec 21, 2007 IP
  7. Agent_Dweeb

    Agent_Dweeb Peon

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    #7
    Agent_Dweeb, Dec 21, 2007 IP
  8. tushardhoot1

    tushardhoot1 Active Member

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    #8
    tushardhoot1, Dec 21, 2007 IP