Add days to date() ???

I use:
$today = date("F - j - Y");

however I want to add a certain number of days to it.
Like: $nextweek = 7

How can I add those 7 days to the current date? and still keep it in the same format.

 

check the example from the manual:

<?php
$tomorrow  = mktime(0, 0, 0, date("m")  , date("d")+1, date("Y"));
$lastmonth = mktime(0, 0, 0, date("m")-1, date("d"),  date("Y"));
$nextyear  = mktime(0, 0, 0, date("m"),  date("d"),  date("Y")+1);
?> 

PHP:

 

Some functions I use with MySQL database :

function dt_only_date_minus_x_days( $x ) {
  return date("Y-m-d", time( ) - ( $x * 24 * 60 * 60 ) );
}

function dt_minus_x_days( $x ) {
  return date("Y-m-d G:i:s", time( ) - ( $x * 24 * 60 * 60 ) );
}

function dt_now( ) {
  return dt_minus_x_days( 0 );
}

function dt_yesterday( ) {
  return dt_minus_x_days( 1 );
}

Code (markup):

Hope It Helps.

 

@olaf2 that returns a timestamp, i need the same format

 

use the timestamp as the second argument of the date function (and maybe take a look in the manual)

 

Try this:

$time = time() + (7 * 24 * 60 * 60);
print $today = date("F - j - Y");              # today
print $today = date("F - j - Y", $time);    # next week

Code (markup):

 

date("F - j - Y", strtotime('+1 week'));

PHP:

 

hey nico_swd, how can I make the +1 a variable so +weeks ? thanks

 

nvm, I used clacey's

thanks very much... rep added to those that helped

 

Like this?

$diff= strtotime('+1 week');

$today = date("F - j - Y");
$nextweek = date("F - j - Y", $diff);

PHP:

 

Use strtotime()

Great function You can figure out a timestamp with this little guy using english like words to do it

$timestamp = strtotime("1 week ago");
$timestamp = strtotime("5 hours later");
$timestamp = strtotime("18 years ago");
$timestamp = strtotime("30 days from now");