.9 repeating = 1

Discussion in 'General Chat' started by kemus, Mar 8, 2007.

  1. #1
    The proof I like the most:

    Clearly
    0.9999... <= 1.
    Assume
    0.9999... != 1 (*).
    Then
    0.9999... < 1,
    so there must be some positive number P so that
    0.9999... + P = 1.
    But for ANY NONZERO positive P,
    0.9999... + P > 1,
    which is a contradiction, and definitely wrong. Therefore we are forced to conclude that the assumption (*) was incorrect, which gives us:
    0.9999... = 1

    Try refuting this one...
    http://mathforum.org/dr.math/faq/faq.0.9999.html
    http://qntm.org/pointnine

    Discuss. :cool:
     
    kemus, Mar 8, 2007 IP