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2 level array, trying to bring data from database

Discussion in 'PHP' started by ameerulislam43, Dec 14, 2016.

0
  1. #1
    I feel like banging my head now. I can't solve it.. doesn't make sense. 

    $sql = "SELECT x,y FROM datapoints ";
$result = $conn->query($sql) ;

if ($result->num_rows > 0) {
    // output data of each row

   
        $dataPoints = array(
     
         while($row = $result->fetch_assoc()) {
            array("x" => $row["x"], "y" => $row["y"])   
if  ($result->num_rows > 1) 
                { echo ",";}

       }  
        );
   
  
} else {
    echo "0 results";
}
    Code (markup):
    I'm getting this error for this code

    My expected outcome is somthing like this

     
    ameerulislam43, Dec 14, 2016 IP
  2. sarahk

    sarahk iTamer Staff

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    #2
    Sometimes it can be good to use a "tidy" or "format" tool to show you where you've gone wrong. I don't use netbeans for day to day editing but it's perfect for the kind of thing you're doing here (and you'll kick yourself when you see it).

    My real comment is more about how you are trying to create that javascript array. What you have as your expected array isn't going to play nicely. Then again you could be doing something else altogether and I've got the wrong end of the stick.

    Try this instead - untested but should be more or less right

    <?php
$sql = "SELECT x,y FROM datapoints ";
$result = $conn->query($sql) ;

if ($result->num_rows > 0) {
    // output data of each row
        $dataPoints = array();
  
         while($row = $result->fetch_assoc()) {
            $dataPoints[] = "{$row['x']} : {$row['y']}";
        );
    echo 'var dataPoints = {'.implode(' , ', $dataPoints).'}';
} else {
    echo "0 results";
}
    PHP:
     
    sarahk, Dec 14, 2016 IP
  3. ameerulislam43

    ameerulislam43 Active Member

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    #3
    Thanks but this one didn't work..


    however this code worked that I got from someone.. 

       if ($result->num_rows > 0) {
        // output data of each row
        while ($row = $result->fetch_assoc()) {
            $dataPoints[] = array("x" => $row["x"], "y" => $row["y"]);
        }
    } else {
        echo "0 results";
    }
    Code (markup):
    I appreciate your help. :)
     
    ameerulislam43, Dec 14, 2016 IP
  4. ThePHPMaster

    ThePHPMaster Well-Known Member

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    #4
    ThePHPMaster, Dec 14, 2016 IP
  5. sarahk

    sarahk iTamer Staff

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    #5
    lol, yeah, that would do it. I thought you needed to echo out the values...
     
    sarahk, Dec 14, 2016 IP
  6. ameerulislam43

    ameerulislam43 Active Member

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    #6
    I know the basics sir! just have less practice. and I think this wasn't that simple syntax question.
     
    ameerulislam43, Dec 14, 2016 IP
  7. sarahk

    sarahk iTamer Staff

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    #7
    It was, you had brackets in all the wrong places.
     
    sarahk, Dec 14, 2016 IP
  8. PoPSiCLe

    PoPSiCLe Illustrious Member

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    #8
    Also, you tried to directly assign array-values with a while-loop inside an array-declaration... So no, you don't know basic syntax.
     
    PoPSiCLe, Dec 14, 2016 IP