Simple Upload Form Question

well I don't see anything wrong in the code, but im probably looking right over the problem. here is the upload function.

	function upload(){
	echo "step1<br/>";
	$path = "img/" . $_GET['id'] . '/' .rand(11,99). $HTTP_POST_FILES['ufile']['name'];
	if($ufile != none){
		echo "step2<br/>";
		if(copy($HTTP_POST_FILES['ufile']['tmp_name'], $path)){
			echo "step3<br/>";
			chmod($path, 0777);
		}
	} else {
		echo'<span style="color:red">Upload Failed</span><br/>';
	}
}

PHP:

and it is returning step1 and step2, but not step3 so something somewhere is going wrong.

before i completely re-write this, does any of you see a problem? thanks!

 

can you post the form?

-> $HTTP_POST_FILES['ufile']['name']
-> $_GET['id']

are these existing? make sure you pass this globaly into the function.. i dont see any parameters in your function

 

<form method='post' action='?act=modify&id=$id' enctype='multipart/form-data'>Add Image <input type="file" name="ufile"/><input type="submit" value="Upload" name="upload"/></form>

PHP:

and the id variable is always set, and i made sure it was being put into the form action correctly which it was.

 

Cant find the error but
regarding this part :

$ufile is? Did u assign a value to it? I see its a function and there isn't anything assignation regarding $ufile

$ufile = $HTTP_POST_FILES['ufile']['name']; // maybe
if($ufile != ''){

PHP:

Anyway this is not the problem as it prints out step2

Try rename instead of copy.