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Opposite of array_search function?

Discussion in 'PHP' started by norfstar, Sep 16, 2005.

  1. #1
    array_search (http://uk.php.net/manual/en/function.array-search.php) searches an array for a value an returns the corresponding key. What I need to do is search an array for a key and return the corresponding value.

    Now I know the first thing you may think is that I'm really silly and forgot it's just $foo[bar]. However, the key itself will be variable, and I can't put $foo[$keynumber] as anyone who is familiar with PHP will know that is incorrect.

    I'm sure it's simple. Can anyone give me a pointer? Thanks :D.
     
    norfstar, Sep 16, 2005 IP
  2. dct

    dct Finder of cool gadgets

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    #2
    I'm not an expert at PHP but you can do
    
    $keyname = 'whateveristhatkeyname';
    echo $foo[$keyname];
    
    PHP:
     
    dct, Sep 16, 2005 IP
  3. norfstar

    norfstar Peon

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    #3
    Unfortunately you can't :(.

    I'm thinking perhaps there is a way to switch the keys and values in an array, then I could use array_search. If anyone knows how this can be done that'd be appreciated :).
     
    norfstar, Sep 16, 2005 IP
  4. dct

    dct Finder of cool gadgets

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    #4
    I don't know if its a version thing but I'm using that method successfully now, I've tested it to make doubly sure and it works fine :confused:

    Can you post some sample code that isn't working?
     
    dct, Sep 16, 2005 IP
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  5. Willy

    Willy Peon

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    #5
    :eek: That's exactly how it's done, in fact the whole point of arrays and hashtables is that you can lookup the value using the key, and of course it can be a variable :confused: dct's example will work perfectly.
     
    Willy, Sep 16, 2005 IP
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  6. norfstar

    norfstar Peon

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    #6
    My mistake :eek:. I'm sure I'd tried that a while back on a different script and it didn't work - maybe like dct said it's a version thing (or maybe I'm just an idiot :eek:).

    Thanks!
     
    norfstar, Sep 16, 2005 IP
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  7. sarahk

    sarahk iTamer Staff

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    #7
    try

    $keyname = 'whateveristhatkeyname';
    if (isset($foo[$keyname])) echo "I've already added {$keyname}";
    Code (markup):
     
    sarahk, Sep 17, 2005 IP