New Variable name in A loop

Discussion in 'PHP' started by qdsouza, Sep 15, 2005.

0
  1. #1
    hi,

    This is probably I really simple problem. I have a loop and want to create a new set of variables each time the loop completes.

    for ( $v=1; $_POST['rown'] >= $v; $v++ ) {
	if ($template == 5) {
		print" <tr>
          <input name=\"$dataa\" type=\"text\" size=\"40\">
          <td bgcolor=\"#FFFFFF\"><input name=\"$dataa\" type=\"text\" size=\"40\"></td>
          <td bgcolor=\"#FFFFFF\"><input name=\"$datab\" type=\"text\" size=\"40\"></td>
          <td bgcolor=\"#FFFFFF\"><input name=\"$datac\" type=\"text\" size=\"40\"></td>
          <td bgcolor=\"#FFFFFF\"><input name=\"$datad\" type=\"text\" size=\"40\"></td>
          <td bgcolor=\"#FFFFFF\"><input name=\"$datae\" type=\"text\" size=\"40\"></td>
</tr>";
	}
    PHP:
    So that dataa in the next loop becomes dataa1, then dataa2 etc. Can I use a concatenate to do this?
     
    qdsouza, Sep 15, 2005 IP
  2. sarahk

    sarahk iTamer Staff

    Messages:
    28,906
    Likes Received:
    4,555
    Best Answers:
    123
    Trophy Points:
    665
    #2
    this should do it
    for ( $v=1; $_POST['rown'] >= $v; $v++ ) {
  if ($template == 5) {
    echo " <tr>
     <input name='$dataa' type='text' size='40'>
     <td bgcolor='#FFFFFF'><input name='dataa{$v}' type='text' size='40'></td>
     <td bgcolor='#FFFFFF'><input name='datab{$v}' type='text' size='40'></td>
     <td bgcolor='#FFFFFF'><input name='datac{$v}' type='text' size='40'></td>
     <td bgcolor='#FFFFFF'><input name='datad{$v}' type='text' size='40'></td>
     <td bgcolor='#FFFFFF'><input name='datae{$v}' type='text' size='40'></td>
   </tr>";
  } 
}
    PHP:
     
    sarahk, Sep 15, 2005 IP
    qdsouza likes this.
  3. qdsouza

    qdsouza Guest

    Messages:
    20
    Likes Received:
    1
    Best Answers:
    0
    Trophy Points:
    0
    #3
    Thanks you are awesome!

    Just curious - Why does $data{$v} work and not a concatentation $add.$v ?
     
    qdsouza, Sep 16, 2005 IP
  4. sarahk

    sarahk iTamer Staff

    Messages:
    28,906
    Likes Received:
    4,555
    Best Answers:
    123
    Trophy Points:
    665
    #4
    because you're already inside a string. The . is seen as plain text.

    {} tells PHP to find a variable to match the variable within (only 1) and not get confused with the other stuff that's plain string. You can leave the {} but it's faster and safer to use it.
     
    sarahk, Sep 16, 2005 IP
  5. qdsouza

    qdsouza Guest

    Messages:
    20
    Likes Received:
    1
    Best Answers:
    0
    Trophy Points:
    0
    #5
    Using the {} method, is it possible to get php to append a variable (with another variable) before it actually evaluates the variable? So if if have $data{$v} is in a loop. I would want the $v to evaluate first and that would lead to a string that was posted from a form.

    So that $data1 would be evaluated from the post ... $data2 $data3 etc.
     
    qdsouza, Sep 17, 2005 IP