Convert date format with PHP

Hi,
I want to convert this date format 18/4/2013 to this format 2013-04-18

How i can do this with PHP?
thanks in advance.

 

<?php
$date = new DateTime('2000-01-01');
echo $date->format('Y-m-d');
?>

Code (markup):

 

Where i can put the string of the initial date format?

 

i want to convert the date format from d/m/yyyy to yyyy-mm-dd

 

Hm, DateTime is a good solution, though I'm not too sure if d/m/Y is a valid format you can pass through to the class constructor. I suspect it may raise an exception. Likewise, you may not be able to convert that string to a Unix timestamp using strtotime in that format as well (though it's worth trying). If that's the case, a simple solution may be to do something like:

<?php
 
list($day, $month, $year) = explode('/', '18/4/2013');
$convertedDate = sprintf('%s-%s-%s', $year, $month, $day);
var_dump($convertedDate);

PHP:

Output:

string(9) "2013-4-18"

Code (markup):

 

this is my solution

$md = explode("/", "18/4/2013"); // split the array
$nd = $md[2]."-".$md[1]."-".$md[0]; // join them together
$mydate = date('Y-m-d', strtotime($nd));

PHP:

 

I suggest using strtotime function to convert the date to a unix timestamp, then you can display it on any format you wish, eg:

$format1 = "18/4/2013";
$timestamp = strtotime($format1);
$format2 = date("Y-m-d", $timestamp);

Code (markup):

 

Relying on php date functions such as strtotime is not safe, because they are using server's locale which also describes date and time formats. You need to specify both formats:

<?
$dt = DateTime::createFromFormat("d/m/Y", "18/4/2013");
echo $dt->format("Y-m-d");
?>

Code (markup):

 

This will not work, since your format is: d/m/Y. As stated on the manual:

Which is the solution Alex Raven posted.

 

You can use explode to break string into array using $arr=explode("-",$da); and then reverse array using array_reverse($arr); and then implode an array using $str= implode("-",$arr); so you will get your result in the $str