PHP Snippet Code Help ...

Hi ... I have the following code embedded in the main page of my website,

<?php


$seenSnippets = $this->session->userdata('seenSnippets');

if(!is_array($seenSnippets))

$seenSnippets = array();

$lastSeenSnippet = $this->session->userdata('lastSeenSnippet');

if(!strlen($lastSeenSnippet))

$lastSeenSnippet = -3;

$snippets = array();

LIST OF SNIPPETS



$unseenSnippets = array_keys($snippets);

if(count($seenSnippets))
{

if(count($seenSnippets) == count($snippets))
$seenSnippets = array($lastSeenSnippet);
$unseenSnippets = array_diff($unseenSnippets,$seenSnippets);
}

// Pick a random one that has not been seen

$snippetIDX = array_rand($unseenSnippets);
$seenSnippets[] = $snippetIDX;
$lastSeenSnippet = $snippetIDX;
$snippet = $snippets[$snippetIDX];

$this->session->set_userdata('seenSnippets', $seenSnippets);

$this->session->set_userdata('lastSeenSnippet', $lastSeenSnippet);

echo $snippet;

?>

Whenever I try to remove a snippet or two from the list, the most recent version of FireFox displays the following error (IE and Chrome work fine),

A PHP Error was encountered

Severity: Notice
Message: Undefined index:
Filename: views/vmain.php
Line Number: 890
Line 890 contains the following code, $snippet = $snippets[$snippetIDX];

Although the code is embedded and there's no specific database for the snippets, I suspect codeignitor caches the snippets somewhere, as this problem is somewhat intermittent. I can't figure out or imagine where the snippets cache might reside.

All browsers are up to date, as of today. My desktop uses Windows 7.

Any ideas, advice or help much appreciated.

dgp

 

It's because the variable has not been set, just place at the top $snippet = ''; that will stop the error.

 

Hi ... thanks for your suggestion. Exactly where, in the code, do I place $snippet = '';? I tried several places, but the error message kept appearing. I cleared the cache before every page refresh. Thanks. dgp

 

Right at the top of the script, don't place it inside as that may overwrite whatever value is it getting set.

 

Hi ... I placed the code on the line following <?php, but the error continues. Here's the top of the code,
<?php

$snippet = '';

$seenSnippets = $this->session->userdata('seenSnippets');

if(!is_array($seenSnippets))

$seenSnippets = array();

$lastSeenSnippet = $this->session->userdata('lastSeenSnippet');

if(!strlen($lastSeenSnippet))


$lastSeenSnippet = -3;

$snippets = array();

Thanks. dgp

 

replace this line:

$snippet = $snippets[$snippetIDX];

PHP:

to

$snippet = (isset($snippets[$snippetIDX])) ? $snippets[$snippetIDX] : 0;

PHP:

Should stop the notice error.

 

Hi ... replaced code; now returns 0 or any any number I replace the 0 with. Thanks. dgp

 

Sorry I need to look at all of the script, can you post the code?

 

Hi ... code in original posting of this thread. Thanks. dgp

 

The error is coming as the $snippetIDX is not getting a value from the array_rand() call. Just set this at the top of the script and remove the changes that I suggested.

ini_set('display_errors', 'Off');
error_reporting(0);

PHP:

This isn't really a good way as we are just hiding the error, but without looking at the whole setup and the session data it's hard work.

 

Hi ... worked. Thanks so much. You don't know how much I appreciate your skill and your time. dgp

 

Your'e welcome, sorry I couldn't get the actual error removed. I would of needed to apply var_dump and had a look at what the sessions values were.