Display Second Or Random Image From Google Image Search

Hello,

I've got the following script which displays the first result from google images, however I'd like it to display either the second or a random image from the specified google image search.

Anyone know how I can do this?

This is the script I currently have:

<?php
 
$link = "http://images.google.com/images?q=".get_the_title()."&tbm=isch";
$link = str_replace(' ','_',$link);
$code = file_get_contents($link,'r');
 
 
ereg ("imgurl=http://www.[A-Za-z0-9-]*.[A-Za-z]*[^.]*.[A-Za-z]*", $code, $img);
ereg ("http://(.*)", $img[0], $img_pic);
 
$firstImage = $img_pic[0];
$firstImage = trim("$firstImage");
echo "";
 
// Display image
echo "<a href=\"$firstImage\">
      <img src=\"$firstImage\" class=\"artimage\">
      </a>";
?>

Code (markup):

 

Unfortunately that doesn't work.

 

function ereg is depracated

 

use preg_match() instead...

preg_match("#imgurl=http://www.[A-Za-z0-9-]*.[A-Za-z]*[^.]*.[A-Za-z]*#", $code, $img);
preg_match("#http://(.*)#", $img[0], $img_pic);

Code (markup):

 

Thanks for the suggestions, however still doesn't appear to be working.

 

 
// .....

preg_match_all('%imgurl=(http|https)://(.+?)&amp%s', $code, $res, PREG_PATTERN_ORDER);
if(!empty($res[2])) {
  $res = $res[2];

  echo $res[1]."\n"; // im image #2
  echo $res[mt_rand(0,(count($res)-1))]."\n"; // im image #random
}

Code (markup):