get file name and image and writes to a file

Hello,
The following script writes to a file include.php

    <?php
    $path = "./files/";
    $path2="http://".$_SERVER['SERVER_NAME'].dirname($_SERVER["PHP_SELF"])."/files/";
    //echo $path2;
    $folder = opendir($path);
    $start="";
    $Fnm = "./include.php";
    $inF = fopen($Fnm,"w");
    fwrite($inF,$start."\n");
    while( $file = readdir($folder) ) {
    if (($file != '.')&&($file != '..')&&($file != 'index.htm')) {
    $result="{\nlevels: [\n{ file: \"$path2$file\" }\n],\n\ntitle: \"$file\"\n},\n";
    fwrite($inF,$result);
    }
    }
    fwrite($inF,"");
    closedir($folder);
    fclose($inF);
    ?>

Code (markup):

It searches the folder and look for any file and store it in $path2$file
so the result posted in include.php is (If the folder has one file)

    {
    levels: [
    { file: "path to/files/filename" }
    ],
    title: "filename"
    },

Code (markup):

and if the folder has 2 files result is

    {
    levels: [
    { file: "path to/files/filename1" }
    ],
    title: "filename2"
    },
    {
    levels: [
    { file: "path to/files/filename2" }
    ],
    title: "filename2"
    },

Code (markup):

and so on...

What I need is to search for another folder /images and write the same image file in include.php just below: { file: "path to/files/filename1" }

So the result will be

     {
    levels: [
    { file: "path to/files/filename1" }
    ],
    image: "path to/images/imagefilename1",
    title: "filename2"
    },

Code (markup):

and it will post the same image path for every image file in images folder

I have tried to incorporate the same code with slight variable changes but I am stuck at using while

Any help ?
I wont mind paying some bucks if anyone help me to solve this