Iam just confuse how many effective way to get top in google. Is google pagerank is also responsible for that. thanks
actually there are hundreds of them. may be more than that. but if you start initially then concentrate in the On page SEO and basic Off page like Back linking and directory submission. Gradually you will understand the other factors too. thanks
Getting top of google entire depends on the backlinks you have for your keywords and It has no relation with page rank.
just be patient to get good rankings in Google, in the mean while you can concentrate on making your site a "quality website" from all perspectives...
you have to create backlinks to ur page as much as u can. either by press reliese, forums, social networking, directory submission, article writng and other SEO ways. As far as google ranking is concerned , yes, it is also responsible as it drives more traffic and traffic inturn increases ur google rankin. the thing for which im confused .... WHY just GOOGLE???
If you are focusing on SEO, just keep doing it. your page rank will automatically increase after some time, this is not something you have to worry about.
Just optimize your site through on page and off page techniques. Update your content in a regular interval and keep link building with high page ranked sites. Getting top in the Google is not an easy task at all as you need to keep patience and work hard for it.
Creating backlinks by submiting directories posts press release etc. but is time consuming way and give late results
It depends upon your keyword competition..You can use se tools to find out the number of backlinks of your competitors, try to beat them by doing more backlinkg than them..it takes time depending upon your competition..
PR and SERPS are 2 diffrent ways Theres no FAST way TO RANK hard work/time/patience even money spent ..
No, page rank is not responsible for ranking. You would see many website of 0 PR ranking above the ones with higher PR. The key is to be able to get the right anchor links from reputed websites.