IP address issue

Hi

I use to determine visitors address with

$ipaddress = $_SERVER['REMOTE_ADDR'];

PHP:

But lately when viewing my own IP address as displayed by this variable I'm getting the IP of Google - pertaining to a Mountain View, CA location. How can this be? I am quite far from California...

Would you recommend using another expression in order to get the real IP?

 

Cool... that means only one thing... You are working for Google

Thomas

 

Yeah, I wish!

Could Googlebot be the cause? Weird.

 

could be due to proxy?

 

Are you using Google Web Accelerator?

If you are going through a proxy, then maybe the original user IP address is stored somewhere in the HTTP headers. Make a call to apache_request_headers(), and have a rummage in the array that gets returned.

Cryo.

 

I have been using this function:

function get_client_ip() {
	if (isset ($_SERVER['HTTP_X_FORWARDED_FOR']))
		$ipAddress = $_SERVER['HTTP_X_FORWARDED_FOR'];
	else
		$ipAddress = $_SERVER['REMOTE_ADDR'];
	return $ipAddress;
}

Code (markup):

Maybe it will help.

 

Oh, yes, that's it: I actually am using Google Web Accelerator! This must be the explanation. Many thanks.

And I'll use the suggested function. Many thanks too.

 

<?php
function get_real_ip()
{
   // No IP found (will be overwritten by for
   // if any IP is found behind a firewall)
   $ip = FALSE;
   
   // If HTTP_CLIENT_IP is set, then give it priority
   if (!empty($_SERVER["HTTP_CLIENT_IP"])) {
       $ip = $_SERVER["HTTP_CLIENT_IP"];
   }
   
   // User is behind a proxy and check that we discard RFC1918 IP addresses
   // if they are behind a proxy then only figure out which IP belongs to the
   // user.  Might not need any more hackin if there is a squid reverse proxy
   // infront of apache.
   if (!empty($_SERVER['HTTP_X_FORWARDED_FOR'])) {

       // Put the IP's into an array which we shall work with shortly.
       $ips = explode (", ", $_SERVER['HTTP_X_FORWARDED_FOR']);
       if ($ip) { array_unshift($ips, $ip); $ip = FALSE; }

       for ($i = 0; $i < count($ips); $i++) {
           // Skip RFC 1918 IP's 10.0.0.0/8, 172.16.0.0/12 and
           // 192.168.0.0/16 -- jim kill me later with my regexp pattern
           // below.
           if (!eregi ("^(10|172\.16|192\.168)\.", $ips[$i])) {
               if (version_compare(phpversion(), "5.0.0", ">=")) {
                   if (ip2long($ips[$i]) != false) {
                       $ip = $ips[$i];
                       break;
                   }
               } else {
                   if (ip2long($ips[$i]) != -1) {
                       $ip = $ips[$i];
                       break;
                   }
               }
           }
       }
   }

   // Return with the found IP or the remote address
   return ($ip ? $ip : $_SERVER['REMOTE_ADDR']);
}
?>

PHP:

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