Php value in an echo request problem

Hi all

Quick question, its stumped me, so am hoping someone can help.

If I want to include a file by way of PHP include, so I would have the following

<?php include (TEMPLATEPATH.'/scripts/comment-templates/FILENAME.php');?> 

Code (markup):

So that works. Now I want to have FILENAME as a variable. So its been set though a different array (it works, I can echo the name correctly with this)

$mb_comment_template_name

Code (markup):

How can I join those together? So $mb_comment_template_name replaces FILENAME in the include lines.

I cant get it to read the variable, it just spits out the variable name not its value.

Thanks to anyone who can help!!!

 

you mean u want to actually include the file $mb_comment_template_name ??

 

<?php include (TEMPLATEPATH."/scripts/comment-templates/$mb_comment_template_name.php");?>

That should replace FILENAME with $mb_comment_template_name.

You cannot use $variables in a string enclosed with ' and '. It needs to be " and ".

If you wanted to use ' and ', you could use the following:

<?php include (TEMPLATEPATH.'/scripts/comment-templates/'.$mb_comment_template_name.'.php');?>

 

yes thats right. So I can define the value of $mb_comment_template_name somewhere else on the site. So if I defined it as "melon" the file location would come back as:

<?php include (TEMPLATEPATH.'/scripts/comment-templates/melon.php');?>

Its gonna be a different value due to user selections, so I cant just hard copy it in. Hope that makes sense!

 

try what Sam Designs posted will do what u want

 

That works! Thank you Sam and Bohra, really helped me out! Thank you very much!!!!!!!

 

Yes, remember that single quoted strings do not expand variables, whereas double quoted strings do.