PHP help

I'll get right to the point

Here is my code for generating the name of the month based on what the number of the month is.

function displayMonth($num)
{
if ($num = 1) {$month = 'January';}
else if ($num = 2) {$month = 'February';}
else if ($num = 3) {$month = 'March';}
else if ($num = 4) {$month = 'April';}
else if ($num = 5) {$month = 'May';}
else if ($num = 6) {$month = 'June';}
else if ($num = 7) {$month = 'July';}
else if ($num = 8) {$month = 'August';}
else if ($num = 9) {$month = 'September';}
else if ($num = 10) {$month = 'October';}
else if ($num = 11) {$month = 'November';}
else if ($num = 12) {$month = 'December';}
else {echo '(!) Month Calculator error!';}

echo $month;
}

Code (markup):

Now for some reason it only displays it as January no matter what month I use!
What is the error here? Or is there a better way of going about this?

 

Change

if($num = 1)

to

if($num == 1)

In fact you'd be better with the following;

switch($num){
  case '1': 
    $month = 'January';
  break;
  case '2': 
    $month = 'February';
  break;
  case '3': 
    $month = 'March';
  break;
  case '4': 
    $month = 'April';
  break;
  case '5': 
    $month = 'May';
  break;
  case '6': 
    $month = 'June';
  break;
  case '7': 
    $month = 'July';
  break;
  case '8': 
    $month = 'August';
  break;
  case '9': 
    $month = 'September';
  break;
  case '10': 
    $month = 'October';
  break;
  case '11': 
    $month = 'November';
  break;
  case '12': 
    $month = 'December';
  break;
  default:
    echo "error";
  break;
}

echo $month;

PHP:

 

Thanks! It worked perfectly!

 

here a little "smarter" version of your function. In this version you can use setlocale() to switch the language for the returned value:

setlocale(LC_TIME, "en_US"); # for english
setlocale(LC_TIME, "de_DE"); # for german
setlocale(LC_TIME, "fi_FI"); # for finnish
....

function displayMonth($num)
{
$month = FALSE;
$num=intval($num);
if ($num>0 && $num<13)
{
$month = strftime('%B', mktime(10,0,0,$num));
}
return $month;
}

Code (markup):

 

Or, even quicker..

echo ($num>0&&$num<=12)?date("F", mktime(0, 0, 0, $num+1, 0, 0)):"error";

Code (markup):

 

Beautiful solution!

 

but it is maybe a problem if $num= 3.56

 

yeah i figured that php should have an internal function that does this for you.

 

Don't be ridiculous!

In any case;

ceil($num) 

PHP:

would fix this problem for if you were really pernickety

 

I do this:

$months = array(1 => 'January', 'February', 'March','April','May','June','July','August','September','October','November','December');

$x=12;

echo $months[$x];

PHP:

 

Bow Down Bow down Bow down