php / html link question

Hello.

I have a gallery and have a value in $bigger wich comes out as "http://linktoimage.com/imagename.jpg" if you print it "print '$bigger'; and now i want to have that link into a html link and wonder if this is possible or how i could to this otherwise? print '<center><a href="$bigger" target="_blank" >test</a></center>'; just comes out as http://linktoimage.com/$bigger right now :/

 

You cant use single quotes when using variables inside the string.

Use " instead

 

i get a "Parse error: syntax error, unexpected T_STRING" as soon as i try that :/

print "<center><a href="plogger_get_detail_link();" target="_blank" >Klicka här för större bild</a></center>";

 

try

print '<div style="text-align:center;"><a href="$bigger" target="_blank" >test</a></div>';

Code (markup):

 

the output is "http://linktoimage.com/$bigger" wich is wrong :/

 

<?php $bigger = trim($bigger,'"') ?>

print '<div style="text-align:center;"><a href="$bigger" target="_blank" >test</a></div>';

 

Is $bigger = "http://linktoimage.com/imagename.jpg"?
Maybe you can put the full code out

 

hello friends
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in another file there is $bigger = plogger_get_detail_link(); and "plogger_get_detail_link()" is what becomes "http://linktoimage.com/imagename.jpg". by just printing $bigger it diplayes the "http://linktoimage.com/imagename.jpg" link without it being a hyperlink ie text only. but i want it to a hyperlink under the text "click here for a larger image" wich is what's not working :/

 

hello

Try this code:
print '<a href="$bigger" target="_blank">'.$bigger.'</a>';

 

or, just turn off PHP parsing before you use the HTML-codes, like this:
?>
<a href="<?php echo $bigger; ?>" target="_blank"><?php echo $bigger; ?></a>
<?php

This can easily be used to separate HTML and PHP codes, and avoiding having to continously watch out for the use of " and/or '