hello, I have got a form with 3 fields (20 form on 1 page). Sometimes there is no entry on title field but there is entry on description and fullpage fields. All i want to do is if there is no entry on title i just do not want to put it into database. How can i do this? $title=$_POST['title'][$i]; $description=$_POST['description'][$i]; $fullpage=$_POST['fullpage'][$i]; $query="INSERT INTO `file` VALUES ('', '".$title."', '".$description."', '".$fullpage."')"; mysql_query($query); echo mysql_error(); $c++; } } echo '<center><b>'. $c.' entries put into database</b></center><br/>'; mysql_close($link); } PHP: Thanks
$title=$_POST['title'][$i]; $description=$_POST['description'][$i]; $fullpage=$_POST['fullpage'][$i]; if($title != ""){ $query="INSERT INTO `file` VALUES ('', '".$title."', '".$description."', '".$fullpage."')"; mysql_query($query); echo mysql_error(); } $c++; } } echo '<center><b>'. $c.' entries put into database</b></center><br/>'; mysql_close($link); } PHP: try this. but $c value doesnt affect.
Without having all the code, I can't figure out what you're doing with "$i" and "$c", but here's how I would do it for a single form submit. <?php if(isset($_POST['submitForm']) { // create the error array for display problems $error = array(); // if the title isn't set, set the error to display for the title // you can add more statements, like for length, invalid characters, etc if(!$_POST['title']) { $error['title'] = "<p>You must enter a title.</p>"; } // same as for title if(!$_POST['description']) { $error['description'] = "<p>You must enter a description.</p>"; } // if there are errors in the form, set a form error to let the user know what's going on, and redisplay the form // else, go forth and submit thine query! if(!empty($error)) { $error['form'] = "<p>There were errors with your submission. Please correct them and resubmit.</p>"; displayForm($error); } else { $title=$_POST['title']; $description=$_POST['description']; $query="INSERT INTO `file` VALUES ('', '".$title."', '".$description."', '".$fullpage."')"; mysql_query($query); $result = mysql_insert_id(); // if there is no insert id, something happened. Set a new error, display the mysql_error, and display the form again // else, everything worked great, so tell the user so.and maybe display the form again. if(!$result) { error['form'] = ("<p>There was an error with the submission. MySQL error: ".mysql_error())."</p>"); displayForm($error); } else { echo("<p>Successfully inserted data!</p>"); //dispalyForm(); } } } function displayForm($error = "") { ?> <?php echo($error['form']); ?> <form method="POST"> <?php echo($error['title']; ?> <p><input type="text" name="title" value="<?php echo($_POST['title']); ?>" /></p> <?php echo($error['description']; ?> <p><input type="text" name="description" value="<?php echo($_POST['description']); ?>" /></p> <p><input type="submit" name="submitForm" value="Submit Form" /></p> </form> <?php } PHP: